Я выполняю упражнение Цезарь из курса CS50, но оно не выполняется.
Вот код:
# include <stdio.h>
# include <cs50.h>
# include <string.h>
# include <stdlib.h>
# include <ctype.h>
int main(int argc, string argv[])
{
if (argc == 2)
{
string key = argv[1];
int l = strlen(key);
for (int i = 0; i < l; i++)
{
// if key[i] is an alphabet character
if (isalpha(key[i]) != 0)
{
printf("Usage: ./caesar key\n");
return 1;
}
}
//change charater to number
int k = atoi(argv[1]);
//print Plaintext
string plaintext = get_string("Plaintext: ");
int n = strlen(plaintext);
char ciphertext[n];
//declare plaintext in ASCII
int nplaintext[n];
//Change plaintext to ASCII
for (int i = 0; i < n; i++)
{
nplaintext[i] = (int)plaintext[i];
}
//Declare ASCII for ciphertext which we name "plusplaintext"
int plusnplaintext[n];
for (int i = 0; i < n; i++)
{
//if Capital
if ((nplaintext[i] < 91) && (nplaintext[i] > 64))
{
plusnplaintext[i] = 65 + ((nplaintext[i] + k) - 65) % 26 ;
}
//if Lowercase
else if ((nplaintext[i] < 123) && (nplaintext[i] > 96))
{
plusnplaintext[i] = 97 + ((nplaintext[i] + k) - 97) % 26 ;
}
//if not character a -> z and A -> Z
else
{
plusnplaintext[i] = nplaintext[i];
}
}
for (int i = 0; i < n; i++)
{
ciphertext[i] = (char)plusnplaintext[i];
}
printf("ciphertext: %s\n", ciphertext);
}
else
{
printf("Usage: ./caesar key\n");
return 1;
}
}
Вот результат проверки 50:
:) caesar.c exists.
:) caesar.c compiles.
**:( encrypts "a" as "b" using 1 as key, output not valid ASCII text**
:) encrypts "barfoo" as "yxocll" using 23 as key
:) encrypts "BARFOO" as "EDUIRR" using 3 as key
:) encrypts "BaRFoo" as "FeVJss" using 4 as key
:) encrypts "barfoo" as "onesbb" using 65 as key
**:( encrypts "world, say hello!" as "iadxp, emk tqxxa!" using 12 as key, output not valid ASCII text**
:) handles lack of argv[1]
Когда я тестирую код, иногда он дает правильный результат, иногда он дает неправильный результат с еще несколькими символами в конце ...
Как я могу исправить свой код?