Есть ли способ в R преобразовать мой столбец DateTime в дату и время в формате («% m /% d /% Y» и «% h /% m /% s»)

Question

У меня есть следующие данные df, включающие столбец даты и времени:

структура (список (DateTime = структура (c (1L, 2L, 8L, 9L, 10L, 11L, 12L, 13L, 14л, 15л, 16л, 17л, 18л, 19л, 21л, 22л, 23л, 24л, 25л, 26л, 27л, 28л, 29л, 30л, 31л, 32л, 33л, 34л, 35л, 36л, 36л, 37л, 38л, 39L, 39L, 40L, 41L, 42L, 43L, 44L, 20L, 45L, 46L, 3L, 4L, 5L, 6L, 7L), .Label = c ("01.04.2015 0:02", " 01.04.2015 1:47 "," 01.04.2015 10:01 "," 01.04.2015 10:06 "," 01.04.2015 10:09 "," 01.04.2015 10 : 10 "," 01.04.2015 10:12 "," 01.04.2015 2:40 "," 01.04.2015 5:32 "," 01.04.2015 6:06 "," 4 / 1/2015 6:12 "," 01.04.2015 7:00 "," 01.04.2015 7:04 "," 01.04.2015 7:12 "," 01.04.2015 7: 14 "," 01.04.2015 7:20 "," 01.04.2015 7:21 "," 01.04.2015 7:22 "," 01.04.2015 7:26 "," 4 / 1/2015 7:31 "," 01.04.2015 7:37 "," 01.04.2015 7:50 "," 01.04.2015 7:55 "," 01.04.2015 8:00 "," 01.04.2015 8:07 "," 01.04.2015 8:12 "," 01.04.2015 8:16 "," 01.04.2015 8:22 "," 04/1 / 2015 8:25 "," 01.04.2015 8:28 "," 01.04.2015 8:29 "," 01.04.2015 8:51 "," 01.04.2015 8:52 " , "01.04.2015 8:55", "01.04.2015 8:59", "01.04.2015 9:00", "01.04.2015" 9:05 "," 01.04.2015 9:16 "," 01.04.2015 9:18 "," 01.04.2015 9:19 "," 01.04.2015 9:26 "," 01.04.2015 9:29 "," 01.04.2015 9:30 "," 01.04.2015 9:46 "," 01.04.2015 9:52 "," 01.04.2015 9 : 57 "), class =" factor ")), class =" data.frame ", row.names = c (NA, -48L))

Answer 1

Вы можете использовать as.POSIXct / strptime в базе R

as.POSIXct(x$DateTime, format = "%m/%d/%Y %H:%M", tz = "UTC")
#OR
#strptime(x$DateTime, format = "%m/%d/%Y %H:%M", tz = "UTC")

или

lubridate::mdy_hm(x$DateTime)

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Если для даты и времени необходимы два отдельных столбца, мы можно сделать

x$DateTime <- as.POSIXct(x$DateTime, format = "%m/%d/%Y %H:%M", tz = "UTC")
transform(x, Date = as.Date(DateTime), Time = format(DateTime, "%T"))


#              DateTime       Date     Time
#1  2015-04-01 00:02:00 2015-04-01 00:02:00
#2  2015-04-01 01:47:00 2015-04-01 01:47:00
#3  2015-04-01 02:40:00 2015-04-01 02:40:00
#4  2015-04-01 05:32:00 2015-04-01 05:32:00
#5  2015-04-01 06:06:00 2015-04-01 06:06:00
#6  2015-04-01 06:12:00 2015-04-01 06:12:00
#....

Answer 2

Мы можем использовать as.POSIXct из base R

df1$DateTime <- as.POSIXct(df1$DateTime, format = "%m/%d/%Y %H:%M")

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Или с mdy_hm из lubridate

library(lubridate)
mdy_hm(df1$DateTime)

Если нам нужны два столбца

library(dplyr)
df1 <- df1 %>%
         mutate(DateTime = mdy_hm(DateTime),
               Date = as.Date(DateTime),
               Time = strftime(DateTime, "%H:%M:%S"))

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Или используя anytime

library(anytime)
anytime(df1$DateTime)