Как самостоятельно присоединиться к воспламеняемым данным?

Question

Я пытался решить проблему самостоятельного левого соединения в библиотеке ignated datatables с использованием псевдонима. Любая идея, пожалуйста?

Моя структура категорий таблиц:

id_categories   | name_categories   | description_categories    | icon_categories   | slug_categories   | parent_categories | sub_parent_categories
1               | monitor           | this is monitor           | monitor.png       | monitor           | 0                 | 0
2               | curved            | this is monitor curved    | monitorcurved.png | curved            | 1                 | 0
3               | tube              | this is monitor tube      | monitortube.png   | tube              | 1                 | 0
4               | 21"               | this is monitor curved 21"| monitorcurved21.png | 21-inc          | 1                 | 2

В контроллере:

$this->datatables->select("t1.id_categories AS t1id, t1.name_categories AS t1name, t2.id_categories AS t2id, t2.name_categories AS t2name, t3.id_categories AS t3id, t3.name_categories AS t3name, t1.description_categories, t1.icon_categories, t1.slug_categories");
$this->datatables->from('categories t1');
$this->datatables->join('categories t2','t2.parent_categories = t1id','left');
$this->datatables->join('categories t3','t3.sub_parent_categories = t1id','left');
return $this->datatables->generate();

В представлении:

{data: "t1id", width: '5%', className: 'text-center', orderable: false},
        {data: "t1.name_categories"},
        {data: "t1.description_categories"},
        {data: "t1.icon_categories", className: "text-center", searchable: false, orderable: false, render: function(data){
            return '<a href="<?= base_url("upload/categories/") ?>'+data+'"><img src="<?= base_url("upload/categories/") ?>'+data+'" height=75 width=75></a>'
        }},
        {data: "t1.slug_categories"},
        {data: "t2name", className: "text-center", searchable: false, orderable: false, render: function(data){
            if (data == 0){
                return "-"
            } else {
                return "ei"
            }
        }},
        {data: "t3name"},
        {data: "t1.status_categories", width: '20%', searchable: false, className: 'text-center', render: function(data){
            if(data == '1') return 'Active'
            else return 'Not Active'
        }},
        {name: "t1id", data: "tid", width: '15%', searchable: false, orderable: false, className: 'text-center', render: function(data){
            return '<a title="Edit Data" href="javascript:void(0);" data-id='+data+' class="edit btn btn-success btn-sm"><i class="fa fa-edit"></i></a> <a title="Delete Data" href="javascript:void(0);" data-id='+data+' class="delete btn btn-danger btn-sm"><i class="fa fa-trash"></i></a>'
        }}

и я получаю эту ошибку

Error Number: 1054
Unknown column 't1id' in 'on clause'
SELECT `t1`.`id_categories` AS `t1id`, `t1`.`name_categories` AS `t1name`, `t2`.`id_categories` AS `t2id`, `t2`.`name_categories` AS `t2name`, `t3`.`id_categories` AS `t3id`, `t3`.`name_categories` AS `t3name`, `t1`.`description_categories`, `t1`.`icon_categories`, `t1`.`slug_categories`
FROM `categories` AS `t1`
LEFT JOIN `categories` `t2` ON `t2`.`parent_categories` = `t1id`
LEFT JOIN `categories` `t3` ON `t3`.`sub_parent_categories` = `t1id`

ОБНОВЛЕНИЕ:

затем, когда я меняю код при соединении:

t2.parent_categories = t1id
t3.sub_parent_categories = t1id

на:

t2.parent_categories = id_categories
t3.sub_parent_categories = id_categories

Я получил ошибку:

Duplicate column name 'id_categories'
SELECT COUNT(*) FROM (SELECT *
FROM `categories` `t1`
LEFT JOIN `categories` `t2` ON `t2`.`parent_categories` = `t1`.`id_categories`
LEFT JOIN `categories` `t3` ON `t3`.`sub_parent_categories` = `t1`.`id_categories`) SqueryAux

Answer 1

$this->datatables->select("t1.id_categories AS t1id, t1.name_categories AS t1name, t2.id_categories AS t2id, t2.name_categories AS t2name, t3.id_categories AS t3id, t3.name_categories AS t3name, t1.description_categories, t1.icon_categories, t1.slug_categories");
$this->datatables->from('categories t1');
$this->datatables->join('categories t2','t2.parent_categories = t1.id_categories','left');
$this->datatables->join('categories t3','t3.sub_parent_categories = t1.id_categories','left');
return $this->datatables->generate();

используйте t1. id_categories вместо t1id, тогда будет отлично работать