Я пытаюсь заставить кнопку «лайк» щелкнуть в самом сердце на странице Instagram и продолжить, мне удалось заставить ее работать без кнопки «лайк» только для того, чтобы оставлять комментарии, но мне бы очень хотелось, если бы она также могла щелкните по сердцу и перейдите к оставшейся части поста и хэштегам. Вот код ниже
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
import random
import sys
import time
class GaryVee:
username = ''
password = ''
hashtags = [
'wanderlust', 'travels',
]
comments = [
'Your posts are amazing', 'Amazing work. Keep going!', 'Your photos are magnificent',
'Your work fascinates me!', 'I like how you put your posts together', 'Great job',
'What a really nice photo, great job!', 'Well done!', 'Your posts are amazing',
]
links = []
price = 0.0
def __init__(self):
self.browser = webdriver.Firefox()
self.login()
self.hustle()
def login(self):
self.browser.get('https://www.instagram.com/accounts/login/?source=auth_switcher')
time.sleep(2)
username_field = self.browser.find_element_by_xpath("//input[@name='username']")
username_field.clear()
username_field.send_keys(self.username)
time.sleep(1)
password_field = self.browser.find_element_by_xpath("//input[@name='password']")
password_field.clear()
password_field.send_keys(self.password)
time.sleep(1)
login_button = self.browser.find_element_by_xpath("//button[@type='submit']")
login_button.click()
time.sleep(2)
def hustle(self):
self.getTopPosts()
self.execute()
self.finalize()
def getTopPosts(self):
for hashtag in self.hashtags:
self.browser.get('https://www.instagram.com/explore/tags/' + hashtag +'/')
time.sleep(2)
links = self.browser.find_elements_by_tag_name('a')
condition = lambda link: '.com/p/' in link.get_attribute('href')
valid_links = list(filter(condition, links))
for i in range(0, 9):
link = valid_links[i].get_attribute('href')
if link not in self.links:
self.links.append(link)
def execute(self):
for link in self.links:
self.browser.get(link)
time.sleep(1)
self.browser.execute_script("window.scrollTo(0, document.body.scrollHeight);")
time.sleep(1)
self.comment()
time.sleep(2)
self.like()
self.price += 0.02
sleeptime = random.randint(18, 28)
time.sleep(sleeptime)
def comment(self):
comment_input = lambda: self.browser.find_element_by_tag_name('textarea')
comment_input().click()
comment_input().clear()
comment = random.choice(self.comments)
for letter in comment:
comment_input().send_keys(letter)
delay = random.randint(1, 7) / 30
time.sleep(delay)
comment_input().send_keys(Keys.RETURN)
def like(self):
# THIS IS THE LINE OF CODE IM HAVING TROUBLE WITH ----
like_button = lambda: self.browser.find_element_by_xpath('//span[@aria-label="like"]').click()
like_button().click()
# IN BETWEEN HERE ----
def finalize(self):
print 'You gave $' + string(self.price) + ' back to the community.'
self.browser.close()
sys.exit()
garyVee = GaryVee()
Это сообщение об ошибке, которое я получаю:
Traceback (most recent call last):
File "test.py", line 106, in <module>
garyVee = GaryVee()
File "test.py", line 28, in __init__
self.hustle()
File "test.py", line 50, in hustle
self.execute()
File "test.py", line 78, in execute
self.like()
File "test.py", line 99, in like
like_button().click()
File "test.py", line 98, in <lambda>
like_button = lambda: self.browser.find_element_by_xpath('//span[@aria-label="like"]').click()
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 394, in find_element_by_xpath
return self.find_element(by=By.XPATH, value=xpath)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 978, in find_element
'value': value})['value']
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 321, in execute
self.error_handler.check_response(response)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/errorhandler.py", line 242, in check_response
raise exception_class(message, screen, stacktrace)