Я пытаюсь, чтобы все косвенные и прямые часы отображались в одной строке, и я знаю, что из-за оператора group by отображаются несколько строк. Тем не менее, я попытался удалить группировку и получил ошибку, что l.CHG_TYPE не включается в агрегат при удалении.
<html><table><body><tr><th>ID</th><th>Billing Period</th><th>Shop</th><th>Shift Code</th><th>Employee #</th><th>Indirect Hours</th><th>Direct Hours</th></tr><tr class="odd"><td>202001404223396</td><td>202001</td><td>Sanitation</td><td>1st</td><td>23396</td><td> </td><td>12.73</td></tr>
<tr><td>202001404223396</td><td>202001</td><td>Sanitation</td><td>1st</td><td>23396</td><td>6.41</td><td> </td></tr>
<tr class="odd"><td>202001205225499</td><td>202001</td><td>Car Shop</td><td>1st</td><td>25499</td><td> </td><td>12.4</td></tr>
<tr><td>202001205225499</td><td>202001</td><td>Car Shop</td><td>1st</td><td>25499</td><td>6.82</td><td> </td></tr>
</table></body></html>
SELECT
CONCAT(l.FISC_PD, l.LOCATION, l.SHIFT_CODE, e.EmpNo) 'ID',
l.FISC_PD 'Billing Period',
CASE
WHEN l.LOCATION = '202' THEN 'Specialty Equipment'
WHEN l.LOCATION = '205' THEN 'Car Shop'
WHEN l.LOCATION = '206' THEN 'Truck Shop'
WHEN l.LOCATION = '404' THEN 'Sanitation'
WHEN l.LOCATION = '212' THEN 'Tire Shop'
ELSE l.LOCATION
END as 'Shop',
CASE
WHEN l.SHIFT_CODE in ('2','6') THEN '1st'
WHEN l.SHIFT_CODE in ('3','4','5') THEN '2nd'
ELSE NULL
END as 'Shift Code',
e.EmpNo 'Employee #',
CASE
WHEN l.CHG_TYPE = 'I' THEN ROUND((SUM(l.DURATION)/36000000),2)
ELSE NULL
END as 'Indirect Hours',
CASE
WHEN l.CHG_TYPE = 'D' THEN ROUND((SUM(l.DURATION)/36000000),2)
ELSE NULL
END as 'Direct Hours'
FROM m5prod.mfive.VIEW_EMP_LABOR_JNL l
LEFT JOIN m5prod.mfive.VIEW_ALL_EMPLOYEES e on e.EmpID = l.EMP_ID
WHERE
l.location not in ('218', '201')
and l.FISC_PD in ('202001', '202002', '202003')
GROUP BY
l.FISC_PD,
e.EmpNo,
l.LOCATION,
l.SHIFT_CODE,
l.CHG_TYPE