Я пытаюсь сгенерировать файл Excel из моей базы данных и загрузить файл с моего веб-сайта, но когда я открываю файл Excel, возникает ошибка «невозможно открыть файл, поскольку формат файла или расширение файла недопустимы». произошло. Итак, это мой код для этого.
Вот мой скрипт:
$(document).ready(function () {
$("#btnExportExcel").click(function (e) {
e.preventDefault();
const deferred = $.Deferred();
var paymentType = $("#transactionTypeDropdown").val();
var paymentStatus = $("#paymentStatusDropdown").val();
var merchantName = $("#merchantNameDropdown").val();
var dateTime = $("#reservation").val().split(" ");
var refNo = $("#refNoInput").val();
var terminalId = $("#terminalID").val();
$.ajax({
type: "POST",
crossOrigin: true,
url: "/api/Transaction/ExportExcel",
headers: {
Accept: "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet",
},
data: {
"Date_1": dateTime[0],
"Date_2": dateTime[2],
"PaymentType": paymentType,
"Status": paymentStatus,
"Outtrade": refNo,
"Merchant": merchantName,
"TerminalID": terminalId
},
success: function (result) {
if (dateTime[0] == dateTime[2]) {
filename = "Transaction_Detail_" + dateTime[0].replace(/\//g, '-') + ".xlsx";
}
else {
filename = "Transaction_Detail_" + dateTime[0].replace(/\//g, '-') + " - "
+ dateTime[2].replace(/\//g, '-') + ".xlsx";
}
var uri = 'data:application/vnd.openxmlformats-officedocument.spreadsheetml.sheet,' + result;
var link = document.createElement("a");
link.href = uri;
link.style = "visibility:hidden";
link.download = filename;
document.body.appendChild(link);
link.click();
document.body.removeChild(link);
},
error: function (jqXHR, exception) {
getErrorMessage(jqXHR, exception);
}
});
return deferred.promise();
});
});
Вот мой C# API:
public class TransactionController : ApiController
{
[AllowAnonymous]
[HttpPost]
[Route("api/Transaction/ExportExcel")]
public HttpResponseMessage ExportExcel(TransactionSearchReq req)
{
TransactionMgr transaction = new TransactionMgr();
List<TransactionRecordRes> transactionList = new List<TransactionRecordRes>();
HttpResponseMessage response = Request.CreateResponse(HttpStatusCode.OK);
MediaTypeHeaderValue mediaType = MediaTypeHeaderValue.Parse("application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
byte[] fileContents;
string fileName;
try
{
// Get transaction records
transactionList = transaction.GetSearchTransactionRecord(req);
if (transactionList.Count() > 0)
{
ExcelPackage.LicenseContext = LicenseContext.NonCommercial;
using (var package = new ExcelPackage())
{
var worksheet = package.Workbook.Worksheets.Add("Sheet1");
// I put data to worksheet here.
fileContents = package.GetAsByteArray();
}
if (fileContents == null || fileContents.Length == 0)
{
response = Request.CreateResponse(HttpStatusCode.InternalServerError);
response.Content = new StringContent("Export file error.", Encoding.Unicode);
return response;
}
else
{
if (string.Compare(req.Date_1, req.Date_2) == 0)
{
fileName = string.Format("Transaction_Detail_{0}.xlsx", req.Date_1.Replace('/', '-'));
}
else
{
fileName = string.Format("Transaction_Detail_{0} - {1}.xlsx", req.Date_1.Replace('/', '-'), req.Date_2.Replace('/', '-'));
}
MemoryStream memoryStream = new MemoryStream(fileContents);
response.Content = new StreamContent(memoryStream);
response.Content.Headers.ContentType = mediaType;
response.Content.Headers.ContentDisposition =
new ContentDispositionHeaderValue("attachment") { FileName = fileName };
return response;
}
}
else
{
response = Request.CreateResponse(HttpStatusCode.InternalServerError);
response.Content = new StringContent("Export file error.", Encoding.Unicode);
return response;
}
}
catch (Exception ex)
{
response = Request.CreateResponse(HttpStatusCode.InternalServerError);
response.Content = new StringContent("Export file error.", Encoding.Unicode);
return response;
}
}
}
Где я ' я ошибаюсь?