Попробуйте сделать это, например, в for loop
?
#!/bin/bash
# create an indexed array with all your databases listed
database_names=( "1" "2" "3" )
# Declare an associative array to store dbname and dump status codes
declare -A all_dbdump_states
for db in "${database_names[@]}"; do
echo "Executing $db dump.."
pg_dump -h localhost -p 5432 -U postgres -d $db -v -f "path/file.backup"
dump_rc=$? # Save exit code of pg_dump process into variable
# After each for loop iteration, append data into array
all_dbdump_states[$db]+=$dump_rc
done
echo -e "\nListing status codes of all dumps:"
for db in "${!all_dbdump_states[@]}"; do
echo "Database [$db] status: ${all_dbdump_states[$db]}"
sleep 1
done
Здесь я echoing
этих pg_dump
строк для улучшения тестов и сделал явную ошибку в команде echo
, чтобы поставить вторая команда завершилась неудачно, с кодом выхода 127:
#!/bin/bash
# create an indexed array with all your databases listed
database_names=( "1" "2" "3" )
# Declare an assotiative array to store dbname and dump status codes
declare -A all_dbdump_states
for db in "${database_names[@]}"; do
echo "Executing $db dump.."
if [[ $db -eq 2 ]]; then
ech "pg_dump -h localhost -p 5432 -U postgres -d 2 -v -f 'path/file.backup'" &>/dev/null
dump_rc=$? # Save exit code of pg_dump process into variable
all_dbdump_states[$db]+=$dump_rc
continue
fi
echo "pg_dump -h localhost -p 5432 -U postgres -d $db -v -f 'path/file.backup'" &>/dev/null
dump_rc=$? # Save exit code of pg_dump process into variable
# After each for loop iteration, append data into array
all_dbdump_states[$db]+=$dump_rc
done
echo -e "\nListing status codes of all dumps:"
for db in "${!all_dbdump_states[@]}"; do
echo "Database [$db] status: ${all_dbdump_states[$db]}"
sleep 1
done
Пример вывода:
$ ./test.sh
Executing 1 dump..
Executing 2 dump..
Executing 3 dump..
Listing status codes of all dumps:
Database [1] status: 0
Database [2] status: 127
Database [3] status: 0