в соответствии с этим вопросом, когда я запускаю мой код скребка python, для какого-то веб-сайта цель состоит в том, чтобы получить эту ошибку:
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
http://www.proxz.com/proxy_list_transparent_0.html
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
https://getproxy.net/en/
Traceback (most recent call last):
File "/usr/lib/python2.7/threading.py", line 801, in __bootstrap_inner
self.run()
File "/usr/lib/python2.7/threading.py", line 1072, in run
self.function(*self.args, **self.kwargs)
TypeError: cdquit() takes exactly 1 argument (6 given)
Exception in thread Thread-238:
Traceback (most recent call last):
File "/usr/lib/python2.7/threading.py", line 801, in __bootstrap_inner
self.run()
File "/usr/lib/python2.7/threading.py", line 1072, in run
self.function(*self.args, **self.kwargs)
TypeError: cdquit() takes exactly 1 argument (6 given)
, что является некоторой частью общий результат выполнения этого кода :
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
http://www.aliveproxy.com/proxy-list-port-80/
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
https://www.englandproxy.co.uk/
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
https://addons.mozilla.org/en-us/firefox/addon/free-proxy-list/
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
https://www.hidetheinternet.com/
Traceback (most recent call last):
File "/usr/lib/python2.7/threading.py", line 801, in __bootstrap_inner
self.run()
File "/usr/lib/python2.7/threading.py", line 1072, in run
self.function(*self.args, **self.kwargs)
TypeError: cdquit() takes exactly 1 argument (6 given)
Exception in thread Thread-222:
Traceback (most recent call last):
File "/usr/lib/python2.7/threading.py", line 801, in __bootstrap_inner
self.run()
File "/usr/lib/python2.7/threading.py", line 1072, in run
self.function(*self.args, **self.kwargs)
TypeError: cdquit() takes exactly 1 argument (6 given)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%proxy find from this url :
http://www.proxylisty.com/port/80-ip-list
, поэтому я протестировал некоторый целевой сайт, такой как:
http://www.proxz.com/proxy_list_transparent_0.html
, который показал фильтр сайта моим провайдером, поэтому я хочу знать, Как я могу обойти все функции python, которые пытаются получить доступ к inte rnet через настройку прокси?
мне быстрее проверить и найти, что модуль python показывает эту ошибку и изменить его настройки для подключения к прокси.
Спасибо.