Как получить json (Карта) в весеннем загрузке jpa для Postgres

Question

PropertyInfo. Java

@Entity
@NoArgsConstructor
@Builder
@AllArgsConstructor
@Table(name = "property_info")
@lombok.Data
@TypeDefs({
        @TypeDef(name = "json", typeClass = JsonStringType.class),
        @TypeDef(name = "jsonb", typeClass = JsonBinaryType.class),
        @TypeDef(name = "jsonb-node", typeClass = JsonNodeBinaryType.class),
        @TypeDef(name = "json-node", typeClass = JsonNodeStringType.class),
        @TypeDef(name = "string-array", typeClass = StringArrayType.class),
        @TypeDef(name = "int-array", typeClass = IntArrayType.class)
})
public class PropertyInfo implements Serializable{
    @Column(name = "property_id")
    private Long propertyId;

    @Type(type = "jsonb")
    @Column(name = "staff", columnDefinition = "jsonb")
    private Map<String, StaffDto> staff;
}

PropertyInfoRepository. Java

@Query(value = "SELECT p.staff->'Center Head' as staff FROM property_info p", nativeQuery = true)
List<PropertyStaffInterface> getUserMapping();

PropertyStaffInterface

 interface PropertyStaffInterface {
    StaffDto getStaff();
}

Данные

персонал

{'Center Head':{"name": "prateek Singh", "role": "Center Head", "user_id": "42727979", "hub_name": "Kochi"}}

персонал -> «начальник центра»

{"name": "prateek Singh", "role": "Center Head", "user_id": "42727979", "hub_name": "Kochi"}

StaffDto. Java

@lombok.Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
public class StaffDto implements Serializable {

  @JsonProperty("role")
  public String role;

  @JsonProperty("user_id")
  public String userId;

  @JsonProperty("name")
  public String name;

  @JsonProperty("hub_name")
  public String hubName;

}

Сведения об ошибке:

org.springframework.orm.jpa.JpaSystemException: No Dialect mapping for JDBC type: 1111; nested exception is org.hibernate.MappingException: No Dialect mapping for JDBC type: 1111

У меня вопрос, как извлечь json объект из Postgres, используя JPA при весенней загрузке?