У меня есть такие данные;
t1<-structure(list(`12/2018` = structure(list(Date = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("12/31/2018",
"3/11/2011"), class = "factor"), X. = structure(c(1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "-", class = "factor"),
Value = c(0.2, 0, 0.1, 0.1, 0, 0, 0, 0, 0, 0, 0, 0, 0)), .Names = c("Date",
"X.", "Value"), row.names = c(NA, 13L), class = "data.frame"),
`3/2011` = structure(list(Date = structure(c(2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("12/31/2018",
"3/11/2011"), class = "factor"), X. = structure(c(1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = "-", class = "factor"),
Value = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)), .Names = c("Date",
"X.", "Value"), row.names = 14:26, class = "data.frame")), .Names = c("12/2018",
"3/2011"))
И я хочу создать фрейм данных с учетом столбца date
для обоих двух объектов в списке, как показано ниже;
df<-data.frame("Day" = , "Month" = , "Year" = )