Я не думаю, что вы можете сделать это с forall
. Вы можете использовать вложенные циклы:
declare
TYPE t_mds_ids IS TABLE OF mds.id%TYPE;
l_mds_ids t_mds_ids;
l_mds_parents t_mds_parents;
begin
SELECT id BULK COLLECT INTO l_mds_ids FROM mds;
l_mds_parents := NEW t_mds_parents();
FOR indx IN l_mds_ids.FIRST .. l_mds_ids.LAST LOOP
FOR rec IN (
select l_mds_ids(indx) as id_employee, ch.id_employee_parent
FROM hierarchy_all ch
CONNECT BY ch.id_employee = prior ch.id_employee_parent
START WITH ch.id_employee = l_mds_ids(indx)
) LOOP
l_mds_parents.extend();
l_mds_parents(l_mds_parents.COUNT)
:= NEW r_mds_parents (rec.id_employee, rec.id_employee_parent);
END LOOP;
END LOOP;
EXECUTE IMMEDIATE 'truncate table mds_hierarchy_all';
insert into mds_hierarchy_all
select * from table(l_mds_parents);
end;
/
Но вам совсем не нужно использовать PL / SQL; используйте один иерархический запрос или, возможно, проще, рекурсивный факторинг подзапросов:
insert into mds_hierarchy_all /* (id_mds, id_employee) -- better to list columns */
with rcte (id_mds, id_employee) as (
select m.id, ha.id_employee_parent
from mds m
join hierarchy_all ha on ha.id_employee = m.id
union all
select r.id_mds, ha.id_employee_parent
from rcte r
join hierarchy_all ha on ha.id_employee = r.id_employee
)
select * from rcte;
db <> fiddle с некоторыми подготовленными данными.