Python3
django == 3.0.5
Hasura v1.1.1
postgres == 11.3
Я пытаюсь использовать фильтр Hasura на IntegerRangeField() and DecimalRangeField(), но застрял сначала
from django.contrib.postgres.fields import DecimalRangeField, IntegerRangeField
from django.db import models
class MyModel(modles.Model):
age = IntegerRangeField()
...
В браузере я запрашиваю эту полезную нагрузку
query MyQuery {
insurance_life_premium(where: {age: {_eq: "47"}}) {
percentage_rate
plan_id
policy_term
premium
sum_insured
}
}
Это вызывает ошибку
{
"errors": [
{
"extensions": {
"path": "$",
"code": "data-exception"
},
"message": "malformed range literal: \"47\""
}
]
}
Я подтверждаю, что в моей базе данных есть действительные данные
In [1]: Premium.objects.filter(age__contains=47)
Out[1]: <QuerySet [<Premium: Premium object (1)>, <Premium: Premium object (60)>, <Premium: , <Premium: Premium object (878)>, '...(remaining elements truncated)...']>
В терминале упоминается о parentheses
hasura_1 | {"type":"http-log","timestamp":"2020-04-29T17:19:08.094+0000","level":"error","detail":{"operation":{"user_vars":{"x-hasura-role":"admin"},"error":{"path":"$","error":"malformed range literal: \"47\"","code":"data-exception"},"request_id":"aab2de87-1095-423e-9eb1-dae34926b226","response_size":78,"query":{"operationName":"MyQuery","query":"query MyQuery {\n insurance_life_premium(where: {age: {_eq: \"47\"}}) {\n percentage_rate\n plan_id\n policy_term\n premium\n sum_insured\n }\n}\n"}},"http_info":{"status":200,"http_version":"HTTP/1.1","url":"/v1/graphql","ip":"172.22.0.1","method":"POST","content_encoding":null}}}
postgres_1 | 2020-04-29 17:19:08.095 UTC [34] ERROR: malformed range literal: "47"
postgres_1 | 2020-04-29 17:19:08.095 UTC [34] DETAIL: Missing left parenthesis or bracket.
postgres_1 | 2020-04-29 17:19:08.095 UTC [34] STATEMENT: SELECT coalesce(json_agg("root" ), '[]' ) AS "root" FROM (SELECT row_to_json((SELECT "_1_e" FROM (SELECT "_0_root.base"."percentage_rate" AS "percentage_rate", "_0_root.base"."plan_id" AS "plan_id", "_0_root.base"."policy_term" AS "policy_term", "_0_root.base"."premium" AS "premium", "_0_root.base"."sum_insured" AS "sum_insured" ) AS "_1_e" ) ) AS "root" FROM (SELECT * FROM "public"."insurance_life_premium" WHERE (("public"."insurance_life_premium"."age") = ($2)) ) AS "_0_root.base" ) AS "_2_root"
query MyQuery {
insurance_life_premium(where: {age: {_eq: "[46]"}}) {
percentage_rate
plan_id
policy_term
premium
sum_insured
}
}
Та же ошибка
"message": "malformed range literal: \"[46]\""
Я пробовал {age: {_in: "(47,]"}} и комбинацию скобок и квадратная скобка. Верни мне пустой список