У меня есть объект Vendor
с полем statusId
:
'use strict';
module.exports = {
up: (queryInterface, Sequelize) => {
return queryInterface.createTable('Vendors', {
id: {
allowNull: false,
autoIncrement: true,
primaryKey: true,
type: Sequelize.INTEGER
},
// other properties
statusId: {
type: Sequelize.INTEGER,
references: {
model: 'VendorStatuses',
key: 'id'
},
onUpdate: 'CASCADE',
onDelete: 'SET NULL'
},
// other properties
});
},
down: (queryInterface, Sequelize) => {
return queryInterface.dropTable('Vendors');
}
};
, связанный с соответствующим VendorStatus
:
'use strict';
module.exports = {
up: (queryInterface, Sequelize) => {
return queryInterface.createTable('VendorStatuses', {
id: {
allowNull: false,
autoIncrement: true,
primaryKey: true,
type: Sequelize.INTEGER
},
name: {
type: Sequelize.STRING
},
});
},
down: (queryInterface, Sequelize) => {
return queryInterface.dropTable('VendorStatuses');
}
};
Модель Vendor
имеет ассоциация:
Vendor.belongsTo(models.VendorStatus, { foreignKey: 'statusId'})
Как я могу получить Sequelize для генерации эквивалента:
SELECT "Vendor"."id", "Vendor"."name",
"VendorStatus"."name" AS "status"
FROM "Vendors" AS "Vendor"
LEFT OUTER JOIN "VendorStatuses" AS "VendorStatus"
ON "Vendor"."statusId" = "VendorStatus"."id";
По сути, я хочу заполнить поле status
VendorStatus.name
в JSON результат я возвращаю клиенту.
Я пытался:
const attribs = ['id', 'name', 'email', ['VendorStatus.name', 'status']];
const vendors = await models.Vendor.findAll({ attributes: attribs, include: [models.VendorStatus] });
, но это дает мне ошибку column "VendorStatus.name" does not exist
. Сгенерировано SQL is:
SELECT "Vendor"."id",
"Vendor"."name",
"Vendor"."email",
"vendorstatus.name" AS "status",
"VendorStatus"."id" AS "VendorStatus.id",
"VendorStatus"."name" AS "VendorStatus.name"
FROM "vendors" AS "Vendor"
LEFT OUTER JOIN "vendorstatuses" AS "VendorStatus"
ON "Vendor"."statusid" = "VendorStatus"."id"
Версии:
[Node: 12.14.1, CLI: 5.5.1, ORM: 5.21.3]