Я пытаюсь взять основной текст и добавить разрывы строк примерно по 80 символов в каждой строке. Проблема, с которой я столкнулся, заключается в последней строке, в которой добавляется дополнительный разрыв строки, чем хотелось бы. Например, в этой строке не должно быть разрывов на предпоследней строке:
Alice was beginning to get very tired of sitting by her sister on the bank, and
of having nothing to do: once or twice she had peeped into the book her sister
was reading, but it had no pictures or conversations in it, and what is the use
of a book, thought Alice without pictures or
conversations?
должно выглядеть так (обратите внимание, что «разговоры» перемещены вверх):
Alice was beginning to get very tired of sitting by her sister on the bank, and
of having nothing to do: once or twice she had peeped into the book her sister
was reading, but it had no pictures or conversations in it, and what is the use
of a book, thought Alice without pictures or conversations?
Вот код:
Sub StringChop()
Dim OrigString As String
Dim NewString As String
Dim counter As Long
Dim length As Long
Dim LastSpace As Long
Dim LineBreak As Long
Dim TempString As String
Dim TempNum As Long
OrigString = "Alice was beginning to get very tired of sitting by her sister on the bank, and of having nothing to do: once or twice she had peeped into the book her sister was reading, but it had no pictures or conversations in it, and what is the use of a book, thought Alice without pictures or conversations?"
length = Len(OrigString)
counter = 1
Do While counter < length
'Extract next 80 characters from last position
TempString = Mid(OrigString, counter, 80)
'Determine last space in string
LastSpace = InStrRev(TempString, " ")
'Determine first line break in string
LineBreak = InStr(TempString, vbNewLine)
'If line break exists in sentence...
'only count characters up to line break, and set counter to that amount
Select Case LastSpace 'What to do if there are spaces in sentence
Case Is > 0 'There are spaces in sentence
Select Case LineBreak 'What to do if there are line breaks in sentence
Case Is = 0
'From last counter position,
NewString = NewString & Mid(OrigString, counter, LastSpace) & vbNewLine
counter = counter + LastSpace
Case Is <> 0
NewString = NewString & Mid(OrigString, counter, LineBreak)
counter = counter + LineBreak
End Select
Case Is = 0 'There are no more spaces left in remaining sentence
NewString = NewString & Mid(OrigString, counter)
counter = length
End Select
Loop
Debug.Print NewString
End Sub