Вы можете использовать запрос иерархии следующим образом:
SQL> with dataa (d) as
2 (select '[["","","2","1","1","1","1","0","0","0","0","0"],["","","0","0","0","1","2","3","2","0","0","0"],["","","0","0","1","2","2","1","1","1","2","0"],["","","0","0","0","1","2","2","2","1","0","0"]]' from dual)
3 -- query starts from here
4 select '[' || ltrim(ltrim(regexp_substr(d,'[^]]+',1,level) || ']',','),'[') as str
5 from dataa
6 connect by level <= regexp_count(d,'\[') - 1;
STR
--------------------------------------------------------------------------------
["","","2","1","1","1","1","0","0","0","0","0"]
["","","0","0","0","1","2","3","2","0","0","0"]
["","","0","0","1","2","2","1","1","1","2","0"]
["","","0","0","0","1","2","2","2","1","0","0"]
SQL>
- Обновление:
SQL> with dataa (d) as
2 (select '[["","","2","1","1","1","1","0","0","0","0","0"],["","","0","0","0","1","2","3","2","0","0","0"],["","","0","0","1","2","2","1","1","1","2","0"],["","","0","0","0","1","2","2","2","1","0","0"]]' from dual)
3 -- query starts from
4 SELECT COALESCE(SUM(CASE WHEN CNTR > 1 THEN 1 END),0) AS CNTR
5 FROM
6 (SELECT T.STR, REGEXP_SUBSTR(T.STR, '[0-9]+',1,COLUMN_VALUE) AS CNTR FROM
7 (select LTRIM(regexp_substr(d,'[^]]+',1,level),',') as str
8 from dataa
9 connect by level <= regexp_count(d,'\[') - 1) T
10 CROSS JOIN
11 table(cast(multiset(select level from dual
12 connect by level <= length (regexp_replace(t.STR, '[^,]+')) + 1)
13 as sys.OdciNumberList)) levels);
CNTR
----------
10
SQL>