Вы на update_trace
далеки от решения. С go.Scattergeo
вы можете использовать параметры mode
и textposition
внутри метода, а с plotly.express
вы должны изменить после.
import plotly.express as px
import pandas as pd
rows=[['501-600','15','122.58333','45.36667'],
['till 500','4','12.5','27.5'],
['more 1001','41','-115.53333','38.08'],
]
colmns=['bins','data','longitude','latitude']
df=pd.DataFrame(data=rows, columns=colmns)
df = df.astype({"data": int})
fig=px.scatter_geo(df,lon='longitude', lat='latitude',
color='bins',
text='data',
opacity=0.5,
size='data',
projection="natural earth")
# This
fig.update_traces(textposition="top center",
mode='markers+text')
fig.show()
** UPDATE **
A возможное решение во избежание проблем в легенде:
import plotly.express as px
import plotly.graph_objs as go
import pandas as pd
rows=[['501-600','15','122.58333','45.36667'],
['till 500','4','12.5','27.5'],
['more 1001','41','-115.53333','38.08'],
]
colmns=['bins','data','longitude','latitude']
df=pd.DataFrame(data=rows, columns=colmns)
df = df.astype({"data": int})
fig=px.scatter_geo(df,lon='longitude', lat='latitude',
color='bins',
opacity=0.5,
size='data',
projection="natural earth")
fig.add_trace(go.Scattergeo(lon=df["longitude"],
lat=df["latitude"],
text=df["data"],
textposition="middle center",
mode='text',
showlegend=False))
fig.show()