PHP Ошибка: вызов функции-члена where () для null в строке 28

Question

Я получаю сообщение об ошибке, когда пытаюсь подсчитать записи в запросе:

public function isLikedBy(User $user)
        {
            return (bool) $user->likes
                ->where('tweet_id', $this->id) //this line returns error
                ->where('liked', true)
                ->count();
        }

Answer 1

@ adam вот моя пользовательская модель. @adam вот это.

<?php

namespace App;

use Illuminate\Contracts\Auth\MustVerifyEmail;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Illuminate\Notifications\Notifiable;


class User extends Authenticatable
{
    use Notifiable, Followable;

    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $guarded = [];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    /**
     * The attributes that should be cast to native types.
     *
     * @var array
     */
    protected $casts = [
        'email_verified_at' => 'datetime',
    ];

    public function getAvatarAttribute($value)
    {
            return asset('storage/' . $value);
    }

    public function setPasswordAttribute($value)
    {
        $this->attributes['password'] = bcrypt($value);
    }

    public function timeline()
    {
        $friends = $this->follows()->pluck('id');

        return Tweet::whereIn('user_id', $friends)->orwhere('user_id', $this->id)->latest()->paginate(50);
    }

    public function tweets()
    {
        return $this->hasMany(Tweet::class)->latest();
    }

    public function path($append = '')
    {
        $path = route('profile', $this->username);

        return $append ? "{$path}/{$append}" : $path ;
    }

}