LEFT JOIN приводит к дублированию строки - ORACLE

Question

Я пишу подзапрос с помощью предложения WITH и присоединяю его к основному запросу. Основной запрос имеет набор результатов из 332 записей, а подзапрос - набор результатов из 302 записей. Если я выполню LEFT JOIN подзапроса к основному запросу, я ожидал бы получить 332, но я получаю 336. Я проверил как основной запрос, так и подзапрос на наличие дубликатов, в частности дублируемых записей и дубликаты не существуют в запросах независимо, почему они возникают в объединении?

WITH FacOwner AS(
    SELECT 
        facility_id_fk, company,
        contact_first_name, contact_last_name,
        contact_title, contact_address1, contact_address2,
        contact_city, contact_state, contact_zipcode_five,
        contact_zipcode_four, contact_phone_number,
        
        sig_first_name, sig_last_name, 
        sig_title, sig_email,
        sig_address1, sig_address2, sig_city, sig_state, 
        sig_zipcode_five, sig_zipcode_four
        
        FROM Contacts
        WHERE Facility_Role = 'Owner'
)

SELECT 
    fg.facility_id_fk,
    fg.general_id_pk,
    fg.facility_name,
    fg.facility_status,
    fg.facility_type,
    fg.landfill_class,
    fg.dshw_staff_person,
    fg.ownership_type,
    loc.county,
    loc.facility_address_street,
    loc.facility_address_city,
    loc.health_department,
    
    FacOwner.company as Owner_Company, (FacOwner.contact_first_name || ' ' || FacOwner.contact_last_name) as OwnerName,  
    FacOwner.contact_title as OwnerTitle, (FacOwner.contact_address1 || FacOwner.contact_address2) as OwnerAddress,
    FacOwner.contact_city as OwnerCity, FacOwner.contact_state as OwnerState, (FacOwner.contact_zipcode_five || '-' || FacOwner.contact_zipcode_four) as OwnerZipcode,
    FacOwner.contact_phone_number as OwnerPhoneNumber,
    
    FacOwner.sig_first_name || ' ' || FacOwner.sig_last_name as OwnerCertSigName,
    FacOwner.sig_title as OwnerCertSigTitle, FacOwner.sig_email as OwnerCertSigEmail,
    (FacOwner.sig_address1 || ' ' || FacOwner.sig_address2) as OwnerCertSigAddress, FacOwner.sig_city as OwnerCertSigCity, FacOwner.sig_state as OwnerCertSigState, 
    (FacOwner.sig_zipcode_five || '-' || FacOwner.sig_zipcode_four) as OwnerCertSigZipcode

FROM facility_general fg
LEFT JOIN facility_location loc ON loc.facility_id_fk = fg.general_id_pk
LEFT JOIN FacOwner on FacOwner.facility_id_fk = fg.general_id_pk
ORDER BY fg.facility_id_fk;

Answer 1

Без репрезентативных данных я могу помочь вам только в устранении неполадок. Чтобы определить проблему, начните со следующего запроса.

Все четыре столбца возвращают одно и то же число?

WITH FacOwner AS(
    SELECT 
        facility_id_fk, company,
        contact_first_name, contact_last_name,
        contact_title, contact_address1, contact_address2,
        contact_city, contact_state, contact_zipcode_five,
        contact_zipcode_four, contact_phone_number,
        
        sig_first_name, sig_last_name, 
        sig_title, sig_email,
        sig_address1, sig_address2, sig_city, sig_state, 
        sig_zipcode_five, sig_zipcode_four
        
        FROM Contacts
        WHERE Facility_Role = 'Owner'
)
SELECT count(*), count(distinct fg.general_id_pk), 
count(distinct FacOwner.facility_id_fk),
count(distinct loc.facility_id_fk)
FROM facility_general fg
LEFT JOIN facility_location loc ON loc.facility_id_fk = fg.general_id_pk
LEFT JOIN FacOwner on FacOwner.facility_id_fk = fg.general_id_pk
ORDER BY fg.facility_id_fk;