Python: проблема с ответом urllib2 - PullRequest
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Python: проблема с ответом urllib2

0 голосов
/ 13 июля 2020

Я пытаюсь вызвать команду curl, используя urllib2. Ниже приведен фрагмент кода. 

with open("blueprint_response.txt", 'r') as f:
 response_data = json.load(f)

Url = 'https://XXX/composition-service/api/blueprints/YYY_no_Chef'

content_header = {'Content-type':'application/json', 'Accept' : 'application/json', 'Authorization' : 'Bearer <token>'}

request = urllib2.Request(url=Url, data = response_data, headers = conten_header)
request.get_method = lambda: 'PUT'

response = urllib2.urlopen(request)

здесь я получаю следующую ошибку. 

Traceback (most recent call last):
  File "2.py", line 20, in <module>
    response = urllib2.urlopen(request)
  File "/usr/lib64/python2.7/urllib2.py", line 154, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib64/python2.7/urllib2.py", line 431, in open
    response = self._open(req, data)
  File "/usr/lib64/python2.7/urllib2.py", line 449, in _open
    '_open', req)
  File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
    result = func(*args)
  File "/usr/lib64/python2.7/urllib2.py", line 1258, in https_open
    context=self._context, check_hostname=self._check_hostname)
  File "/usr/lib64/python2.7/urllib2.py", line 1211, in do_open
    h.request(req.get_method(), req.get_selector(), req.data, headers)
  File "/usr/lib64/python2.7/httplib.py", line 1056, in request
    self._send_request(method, url, body, headers)
  File "/usr/lib64/python2.7/httplib.py", line 1090, in _send_request
    self.endheaders(body)
  File "/usr/lib64/python2.7/httplib.py", line 1052, in endheaders
    self._send_output(message_body)
  File "/usr/lib64/python2.7/httplib.py", line 894, in _send_output
    self.send(message_body)
  File "/usr/lib64/python2.7/httplib.py", line 866, in send
    self.sock.sendall(data)
  File "/usr/lib64/python2.7/ssl.py", line 744, in sendall
    v = self.send(data[count:])
TypeError: unhashable type

Что я здесь делаю? файл json действительный. Пожалуйста помоги. Заранее спасибо

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