В SQLite.swift подзапрос не работает, потому что parsentesis () отсутствует

Question

В SQLite.swift подзапрос не работает из-за отсутствия parsentesis ().

    let users = Table(kUsersTableName)
    let users_types = Table(kUsersTypesTableName)
    let agendas = Table(kAgendasTableName)

    let agendas_query = agendas
        .select(agendas[agenda_date])
        .filter(users[user_id] == agendas[user_id])
        .filter(agendas[agenda_date] < _timestamp)
        .order(agendas[agenda_date].desc)
        .limit(1)

    let query = users
        .select(agendas_query, users[*])
        .join(.leftOuter, users_types, on: users[type_id] == users_types[type_id])
        .order(users[surname].desc, users[name].desc)

Неверный вывод SQL Запрос:

    "SELECT SELECT "agendas"."agenda_date" FROM "agendas" WHERE (("users"."user_id" = "agendas"."user_id") AND ("agendas"."agenda_date" < ?)) ORDER BY "agendas"."agenda_date" DESC LIMIT 1, "users".* FROM "users" LEFT OUTER JOIN "users_types" ON ("users"."type_id" = "users_types"."type_id") ORDER BY "users"."surname" DESC, "users"."name" DESC"

Запрос должен быть:

    "SELECT (SELECT "agendas"."agenda_date" FROM "agendas" WHERE (("users"."user_id" = "agendas"."user_id") AND ("agendas"."agenda_date" < ?)) ORDER BY "agendas"."agenda_date" DESC LIMIT 1), "users".* FROM "users" LEFT OUTER JOIN "users_types" ON ("users"."type_id" = "users_types"."type_id") ORDER BY "users"."surname" DESC, "users"."name" DESC"