Буквально следуя тому, что вы сказали: есть таблица с 3 идентификаторами и их датами, и вы хотите построить график календарь.
Используя иерархический запрос, даты генерируются как
SQL> with
2 threeid (id, datum) as
3 (select 1, date '2020-05-29' from dual union all
4 select 2, date '2020-01-01' from dual union all
5 select 3, date '2020-02-29' from dual
6 ),
7 cal as
8 (select add_months(datum, -6) + column_value - 1 datum
9 from threeid cross join
10 table(cast(multiset(select level from dual
11 connect by level <= add_months(datum, 6) - add_months(datum, -6)
12 ) as sys.odcinumberlist))
13 where id = 1 --> for the 1st ID; change that for other calendars
14 )
15 select * from cal order by datum;
DATUM
----------
29.11.2019
30.11.2019
01.12.2019
02.12.2019
03.12.2019
<snip>
25.11.2020
26.11.2020
27.11.2020
28.11.2020
366 rows selected.
Если вы хотите построить график , вместо строки # 15 вы должны использовать this ...
<snip>
15 select lpad(month, 20, ' ') month,
16 "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", "Sun"
17 from (select to_char(dt, 'fmMonthfm YYYY') month,
18 week,
19 max(decode(to_char(dt, 'd'), '1', lpad(to_char(dt, 'fmdd'), 2))) "Mon",
20 max(decode(to_char(dt, 'd'), '2', lpad(to_char(dt, 'fmdd'), 2))) "Tue",
21 max(decode(to_char(dt, 'd'), '3', lpad(to_char(dt, 'fmdd'), 2))) "Wed",
22 max(decode(to_char(dt, 'd'), '4', lpad(to_char(dt, 'fmdd'), 2))) "Thu",
23 max(decode(to_char(dt, 'd'), '5', lpad(to_char(dt, 'fmdd'), 2))) "Fri",
24 max(decode(to_char(dt, 'd'), '6', lpad(to_char(dt, 'fmdd'), 2))) "Sat",
25 max(decode(to_char(dt, 'd'), '7', lpad(to_char(dt, 'fmdd'), 2))) "Sun"
26 from ( select dt,
27 case when dt >= to_date(to_char(dt, 'dd/') ||'12/'||
28 to_char(sysdate,'yyyy'), 'dd/mm/yyyy')
29 and wk = '01'
30 then '53'
31 else wk
32 end week
33 from (select datum dt, to_char(datum, 'iw') wk
34 from cal
35 )
36 )
37 group by to_char(dt, 'fmMonthfm YYYY'), week
38 )
39 order by to_date( month, 'Month YYYY' ), to_number(week);
.. . и получите , что :
MONTH Mon Tue Wed Thu Fri Sat Sun
-------------------- -------- -------- -------- -------- -------- -------- --------
November 2019 29 30
December 2019 30 31
December 2019 1
December 2019 2 3 4 5 6 7 8
December 2019 9 10 11 12 13 14 15
December 2019 16 17 18 19 20 21 22
December 2019 23 24 25 26 27 28 29
January 2020 1 2 3 4 5
January 2020 6 7 8 9 10 11 12
January 2020 13 14 15 16 17 18 19
January 2020 20 21 22 23 24 25 26
January 2020 27 28 29 30 31
February 2020 1 2
February 2020 3 4 5 6 7 8 9
February 2020 10 11 12 13 14 15 16
February 2020 17 18 19 20 21 22 23
February 2020 24 25 26 27 28 29
March 2020 1
March 2020 2 3 4 5 6 7 8
March 2020 9 10 11 12 13 14 15
March 2020 16 17 18 19 20 21 22
March 2020 23 24 25 26 27 28 29
March 2020 30 31
April 2020 1 2 3 4 5
April 2020 6 7 8 9 10 11 12
April 2020 13 14 15 16 17 18 19
April 2020 20 21 22 23 24 25 26
April 2020 27 28 29 30
May 2020 1 2 3
May 2020 4 5 6 7 8 9 10
May 2020 11 12 13 14 15 16 17
May 2020 18 19 20 21 22 23 24
May 2020 25 26 27 28 29 30 31
June 2020 1 2 3 4 5 6 7
June 2020 8 9 10 11 12 13 14
June 2020 15 16 17 18 19 20 21
June 2020 22 23 24 25 26 27 28
June 2020 29 30
July 2020 1 2 3 4 5
July 2020 6 7 8 9 10 11 12
July 2020 13 14 15 16 17 18 19
July 2020 20 21 22 23 24 25 26
July 2020 27 28 29 30 31
August 2020 1 2
August 2020 3 4 5 6 7 8 9
August 2020 10 11 12 13 14 15 16
August 2020 17 18 19 20 21 22 23
August 2020 24 25 26 27 28 29 30
August 2020 31
September 2020 1 2 3 4 5 6
September 2020 7 8 9 10 11 12 13
September 2020 14 15 16 17 18 19 20
September 2020 21 22 23 24 25 26 27
September 2020 28 29 30
October 2020 1 2 3 4
October 2020 5 6 7 8 9 10 11
October 2020 12 13 14 15 16 17 18
October 2020 19 20 21 22 23 24 25
October 2020 26 27 28 29 30 31
November 2020 1
November 2020 2 3 4 5 6 7 8
November 2020 9 10 11 12 13 14 15
November 2020 16 17 18 19 20 21 22
November 2020 23 24 25 26 27 28
64 rows selected.
SQL>
(Этот красивый календарный запрос изначально (по крайней мере, я так думаю) размещен на OraFAQ сайт; Настроил, надеясь, что правильно отображает даты)