from math import floor
def check_if_number_exists(number, digit_to_find):
# check if the number is positive
if number < 0:
Number = -number
else:
Number = number
while(Number != 0):
# run loop for extracting each digit
Digit = Number % 10 # gives the last number
Number = floor(Number / 10) # removing the last digit
if Digit == digit_to_find:
print("the number contains " + str(digit_to_find) + ' in ' + str(number))
break
# sequencenumber, number_to_check
check_if_number_exists(45638, 3)
Есть и другой способ: преобразовать число в строку, а затем проверить каждый элемент строки!