K-кратное масштабирование изображения с использованием python - PullRequest
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K-кратное масштабирование изображения с использованием python

0 голосов
/ 21 июня 2020

Input image

I have been trying to implement the algorithm for K times zooming on the above image as an input image. Below is my code:

img = cv2.imread("dog2.jpeg",1)
K = int(input("Enter the value of K: "))
x,y,c=img.shape
image = np.zeros((K * img.shape[0] - K + 1, K * img.shape[1] - K + 1,3),np.uint8)

for i in range(img.shape[0]):
    for j in range(img.shape[1] - 1):
        c0 = (int(img[i,j+1,0]) - int(img[i,j,0]))/K
        c1 = (int(img[i,j+1,1]) - int(img[i,j,1]))/K
        c2 = (img[i,j+1,2] - img[i,j,2])/K
        for k in range(1,K):
            image[K*i,K*j+k,0] = image[K*i,K*j+k-1,0] + c0
            image[K*i,K*j+k,1] = image[K*i,K*j+k-1,1] + c1
            image[K*i,K*j+k,2] = image[K*i,K*j+k-1,2] + c2

for j in range(img.shape[1]):
    for i in range(img.shape[0] - 1):
        c0 = (int(img[i+1,j,0]) - int(img[i,j,0]))/K
        c1 = (int(img[i+1,j,1]) - int(img[i,j,1]))/K
        c2 = (int(img[i+1,j,2]) - int(img[i,j,2]))/K
        for k in range(1,K):
            image[K*i+k,K*j,0] = image[K*i+k-1,K*j,0] + c0
            image[K*i+k,K*j,1] = image[K*i+k-1,K*j,1] + c1
            image[K*i+k,K*j,2] = image[K*i+k-1,K*j,2] + c2

I am getting the result shown below but obviously that not the result I am expecting and it's just a zoomed version of the input image. Where am I going wrong? Can someone please correct this.

Выходное изображение

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