java.io.EOFException при написании и чтении сервлета froma - PullRequest
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java.io.EOFException при написании и чтении сервлета froma

3 голосов
/ 19 апреля 2010

У меня есть следующий код на стороне апплета: 

URL servlet = new URL(appletCodeBase, "FormsServlet?form=requestRoom");
URLConnection con = servlet.openConnection();

con.setDoOutput(true);
con.setDoInput(true);
con.setUseCaches(false);
con.setRequestProperty("Content-Type", "application/octet-stream");

ObjectOutputStream out = new ObjectOutputStream(con.getOutputStream());
out.writeObject(user);//user is an object of a serializable class
out.flush();
out.close();

ObjectInputStream in = new ObjectInputStream(con.getInputStream());
status = (String)in.readObject();
in.close();
if("success".equals("status")) {
    JOptionPane.showMessageDialog(rootPane, "Request submitted successfully.");
} else {
    JOptionPane.showMessageDialog(rootPane, "ERROR! Request cannot be made at this 
    time");
}

На стороне сервлета я получаю код следующим образом: 

    form = request.getParameter("form");
    if("requestRoom".equals(form)) {
        String fullName, eID, reason;
        UserRequestingRoom user;

        try {
            in = new ObjectInputStream(request.getInputStream());
            user = (UserRequestingRoom)in.readObject();
            fullName = user.getFullName();
            eID = user.getEID();
            reason = user.getReason();

            Class.forName("com.mysql.jdbc.Driver");
            Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/chat_applet","root","");
            PreparedStatement statement = con.prepareStatement("INSERT INTO REQCONFROOM VALUES(\"" + fullName + "\",\"" + eID + "\",\"" + reason + "\")");
            statement.execute();

            out = new ObjectOutputStream(response.getOutputStream());
            out.writeObject("success");
            out.flush();

        } catch (Exception e)  {
            e.printStackTrace();
            out = new ObjectOutputStream(response.getOutputStream());
            out.writeObject("fail");
            out.flush();
        }
    }

Когда я нажимаю кнопку, которая вызывает код на стороне апплета, я получаю следующую ошибку: 

java.io.EOFException
    at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source)
    at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source)
    at java.io.ObjectInputStream.readStreamHeader(Unknown Source)
    at java.io.ObjectInputStream.<init>(Unknown Source)
    at com.org.RequestRoomForm.requestActionPerformed(RequestRoomForm.java:151)

    **//Line 151 is "ObjectInputStream in..." line in the applet code**

    at com.org.RequestRoomForm.access$000(RequestRoomForm.java:7)
    at com.org.RequestRoomForm$1.actionPerformed(RequestRoomForm.java:62)
    at javax.swing.AbstractButton.fireActionPerformed(Unknown Source)
    at javax.swing.AbstractButton$Handler.actionPerformed(Unknown Source)
    at javax.swing.DefaultButtonModel.fireActionPerformed(Unknown Source)
    at javax.swing.DefaultButtonModel.setPressed(Unknown Source)
    at javax.swing.plaf.basic.BasicButtonListener.mouseReleased(Unknown Source)
    at java.awt.Component.processMouseEvent(Unknown Source)
    at javax.swing.JComponent.processMouseEvent(Unknown Source)
    at java.awt.Component.processEvent(Unknown Source)
    at java.awt.Container.processEvent(Unknown Source)
    at java.awt.Component.dispatchEventImpl(Unknown Source)
    at java.awt.Container.dispatchEventImpl(Unknown Source)
    at java.awt.Component.dispatchEvent(Unknown Source)
    at java.awt.LightweightDispatcher.retargetMouseEvent(Unknown Source)
    at java.awt.LightweightDispatcher.processMouseEvent(Unknown Source)
    at java.awt.LightweightDispatcher.dispatchEvent(Unknown Source)
    at java.awt.Container.dispatchEventImpl(Unknown Source)
    at java.awt.Window.dispatchEventImpl(Unknown Source)
    at java.awt.Component.dispatchEvent(Unknown Source)
    at java.awt.EventQueue.dispatchEvent(Unknown Source)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.run(Unknown Source)

Почему я получаю эту ошибку? Я сбросил при выводе, я также закрыл соединения, но я получаю сообщение об ошибке. Есть причина для этого?

Ответы [ 2 ]

10 голосов
/ 08 июня 2010

Закрыть ObjectOutputStream в конце. 

ObjectOutputStream out = new ObjectOutputStream(con.getOutputStream());
out.writeObject(user);//user is an object of a serializable class
out.flush();
out.close(); //Don,t close your out here

ObjectInputStream in = new ObjectInputStream(con.getInputStream());
status = (String)in.readObject();
in.close();

out.close(); //Close your out after reading the input
0 голосов
/ 13 июля 2016

первый request.getParameter()
тогда request.getInputStream()

в этом случае должно быть исключение курса на tomcat, но не исключение курса на weblogic

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