Код, который вы перечислили, является неполным / непонятным, но код ниже показывает, как взять ResultSet с произвольным числом столбцов и отобразить его содержимое в JTable.
import java.sql.ResultSet;
import java.sql.ResultSetMetaData;
import java.util.ArrayList;
private void viewTable(){
//Perform database query here, which will open a Connection to the database
//Assume we use the above query to populate a ResultSet results
//Get information about the ResultSet
ResultSetMetaData metaData = results.getMetaData();
//Gets the number of columns in results
int columnCount = metaData.getColumnCount();
//Gets the name of each column in results
String[] columnNames = new String[columnCount];
for(int i = 0; i < columnNames.length; i++){
columnNames[i] = metaData.getColumnLabel(i+1);
}
//You can use a String[] to keep track of the rows if you know the #
//# of rows in the ResultSet, this implementation assumes that we don't
//This ArrayList will keep track of each row in results (each row is
//represented by a String[]
ArrayList<String[]> rows = new ArrayList<>();
while(results.next()){
//Fetch each row from the ResultSet, and add to ArrayList of rows
String[] currentRow = new String[columnCount];
for(int i = 0; i < columnCount; i++){
//Again, note that ResultSet column indecies start at 1
currentRow[i] = results.getString(i+1);
}
rows.add(currentRow);
}
//Close Connection to the database here
String[][] rowsArray = new String[rows.size()][columnCount];
rowsArray = rows.toArray(rowsArray);
table = new JTable(rowsArray, columnNames);
}