Вы можете использовать процедуру, но вот простой способ сделать это на SQL:
select greatest(q1,q2,q3,q4,q5) as highest_1,
least( greatest(q1,q2,q3,q4),
greatest(q1,q2,q3,q5),
greatest(q1,q2,q4,q5),
greatest(q1,q3,q4,q5),
greatest(q2,q3,q4,q5) ) as highest_2
from ( SELECT AVG(q1) AS q1,
AVG(q2) AS q2,
AVG(q3) AS q3,
AVG(q4) AS q4,
AVG(q5) AS q5
FROM tresults_acme ) t;
протестировано с:
create view tresults_acme as select 1 as q1, 2 as q2, 3 as q3, 4 as q4, 5 as q5;
результат:
highest_1 | highest_2
--------------------+--------------------
5.0000000000000000 | 4.0000000000000000