Для меня, используя код из Алекс Куль , request.GET['qqfile'] имел имя файла и request.read() (в Django 1.3) вернул данные.
request.FILES использовался только в сценарии, который еще не произошел для меня. Я использую ajax-upload для прямой связи с Photologue, и мой код выглядит примерно так:
def save_upload( uploaded, filename, raw_data ):
"""
raw_data: if True, upfile is a HttpRequest object with raw post data
as the file, rather than a Django UploadedFile from request.FILES
"""
try:
filename = os.path.normpath(os.path.join(IMAGE_UPLOAD_PATH, filename))
with BufferedWriter( FileIO( filename, "wb" ) ) as dest:
# if the "advanced" upload, read directly from the HTTP request
# with the Django 1.3 functionality
if raw_data:
(dirName, fileName) = os.path.split(filename)
(fileBaseName, fileExtension)=os.path.splitext(fileName)
#
# right here, if fileBaseName is less than n characters, might want to slap on a date just for fun
#
try:
i_can_has_p = Photo.objects.get(title=fileBaseName)
title = fileBaseName + "_" + str(datetime.datetime.now().strftime("%Y%m%dT%H%M%S"))
except Photo.DoesNotExist:
title = fileBaseName
title_slug = slugify(title)
p = Photo(title=title, title_slug=title_slug)
p.image.save(filename,ContentFile(uploaded.read()))
# if not raw, it was a form upload so read in the normal Django chunks fashion
else:
# TODO: figure out when this gets called, make it work to save into a Photo like above
for c in uploaded.chunks( ):
dest.write( c )
except IOError:
# could not open the file most likely
return False
return True
def ajax_upload( request ):
if request.method == "POST":
# AJAX Upload will pass the filename in the querystring if it is the "advanced" ajax upload
if request.is_ajax( ):
# the file is stored raw in the request
upload = request
is_raw = True
try:
filename = request.GET[ 'qqfile' ]
except KeyError:
return HttpResponseBadRequest( "AJAX request not valid" )
# not an ajax upload, so it was the "basic" iframe version with submission via form
else:
is_raw = False
if len( request.FILES ) == 1:
# FILES is a dictionary in Django but Ajax Upload gives the uploaded file an
# ID based on a random number, so it cannot be guessed here in the code.
# Rather than editing Ajax Upload to pass the ID in the querystring, note that
# each upload is a separate request so FILES should only have one entry.
# Thus, we can just grab the first (and only) value in the dict.
upload = request.FILES.values( )[ 0 ]
else:
raise Http404( "Bad Upload" )
filename = upload.name
# save the file
success = save_upload( upload, filename, is_raw )
# let Ajax Upload know whether we saved it or not
ret_json = { 'success': success, }
return HttpResponse( json.dumps( ret_json ) )
В моем случае ajax_upload - это функция, вызываемая action: параметром ajax