Хорошо, я динамически генерирую координаты ячейки, но я получаю эту ошибку, почему?
Ошибка:
Exception: Invalid cell coordinate. in /var/www/test/excel/pe/Classes/PHPExcel/Cell.php on line 490
Call Stack:
0.0003 81132 1. {main}() /var/www/test/excel/createExcelReport.php:0
0.0225 2691000 2. PHPExcel_Worksheet->setCellValue() /var/www/test/excel/createExcelReport.php:92
0.0225 2691316 3. PHPExcel_Worksheet->getCell() /var/www/test/excel/pe/Classes/PHPExcel/Worksheet.php:841
0.0597 8336788 4. PHPExcel_Cell::coordinateFromString() /var/www/test/excel/pe/Classes/PHPExcel/Worksheet.php:940
Вот код:
<code>// Add some data
echo date('H:i:s') . " Add some data<br />\n";
$objPHPExcel->setActiveSheetIndex(0);
// *********************** TEST ************************************ //
// Set the defaults
$limit_col = 6;
$limit_row = 10;
$current_col = 'A';
$current_row = 1;
// Create the row and column arrays starting at index 1
$row_arr = array(1 => $current_row);
$column_arr = array(1 => $current_col);
// Build the column array
while(count($column_arr) < $limit_col) {
$column_arr[] = ++$current_col;
}
// Build the row array
while(count($row_arr) < $limit_row) {
$row_arr[] = ++$current_row;
}
//echo "Row<pre>".print_r($row_arr, true)."
Колонка "; // echo"
".print_r($column_arr, true)."
"; foreach ($ row_arr как $ row_number) {$ excel_matrix [$ row_number] = $ column_arr;} foreach ($ excel_matrix как $ row_number => $ column_position) {foreach ($ column_position как $ column_key => $ column_value) {$ ячейка= (строка) $ row_number. ''. $ column_value; echo "Cell:". $ cell. "\ n "; $ objPHPExcel-> getActiveSheet () -> SetCellValue ($ cell, 'Hello');}} // ***********************ТЕСТ ************************************ // // $ objPHPExcel-> getActiveSheet () ->SetCellValue ('A1', 'Hello'); // $ objPHPExcel-> getActiveSheet () -> SetCellValue ('B2', 'world!'); // $ objPHPExcel-> getActiveSheet () -> SetCellValue ('C1', 'Hello'); // $ objPHPExcel-> getActiveSheet () -> SetCellValue ('D2', 'world!');