отобразить 3 верхние записи через запятую в одном столбце

Question

Я столкнулся с проблемой, что мне нужно отобразить 3 верхние записи для каждого aId в строке через запятую в одном столбце (например, aId = 151 ghghg, ghh, rgtg ) вместо приведенного нижерезультат.Кто-нибудь может мне помочь, пожалуйста?

Expertise
  ghghg
  ghh
  rgtg
  rtrt
  ghgh
  tyuyu
  fgfg
  yuu
  dfdf
  gtyy
  dfdf
  df
  ssd
  dfd
  dfdf
  fd
  dfdf
  dd
  sdsds
  hghg
  hgh
  sdds
  dff
  rtrr
  fgfg
  bnbnb
  sdss

create table Expertise(
  Id                   bigint      not null identity constraint PK_Expertise primary key,
  aId                  bigint      not null,
  Expertise            varchar(25) not null,
  NoInMonthsExperience int,
  IsPrimary            bit,
  sId                  bigint      constraint DF_Expertise_sId default (0)
)
go

INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (62, 43, N'sds', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (63, 43, N'gg', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (78, 151, N'ghghg', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (79, 151, N'ghh', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (80, 151, N'rgtg', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (81, 151, N'rtrt', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (82, 151, N'ghgh', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (83, 151, N'tyuyu', 6, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (84, 151, N'fgfg', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (85, 151, N'yuu', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (86, 151, N'dfdf', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (87, 151, N'gtyy', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (88, 151, N'dfdf', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (89, 151, N'df', 3, 1, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (90, 151, N'ssd', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (91, 151, N'dfd', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (92, 151, N'dfdf', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (93, 151, N'fd', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (94, 151, N'dfdf', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (95, 151, N'dd', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (97, 151, N'sdsds', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (98, 151, N'hghg', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (99, 151, N'hgh', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (100, 151, N'sdds', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (101, 151, N'dff', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (102, 151, N'rtrr', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (103, 151, N'fgfg', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (104, 151, N'bnbnb', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (105, 151, N'sdss', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (108, 153, N'hgh', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (109, 153, N'ghg', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (110, 153, N'554', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (111, 153, N'ghg', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (112, 153, N'fttr', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (113, 154, N'.NEt', 5, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (114, 154, N'Java', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (115, 154, N'PHP', 3, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (151, 168, N'ghgh', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (152, 168, N'sdssd', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (183, 156, N'909', 7, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (185, 156, N'tyty', 6, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (193, 185, N'asas', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (194, 184, N'.Net', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (195, 184, N'Php', 4, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (196, 168, N'sdsd', 23, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (197, 168, N'wew12', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (198, 168, N'qwqw', 2, 0, 1)
INSERT [dbo].[Expertise] ([Id], [aId], [Expertise], [NoInMonthsExperience], [IsPrimary], [sId]) VALUES (199, 168, N'erer', 24, 0, 1)

Answer 1

Использование:

SELECT e.ald,
            STUFF(SELECT TOP 3 
                                              ', '+x.enterprise                
                                    FROM dbo.Enterprise x
                                  WHERE x.ald = e.ald
                                FOR XML PATH ('')),1,2,'')
  FROM ENTERPRISE e
GROUP BY e.ald

Answer 2

Я предполагаю, что «тройка лидеров» - три наиболее часто встречающихся элемента в столбце «Экспертиза», но это можно изменить, если это не то, что вы имели ввиду.

WITH T1 AS (
    SELECT TOP(3) Expertise, COUNT(*) AS cnt
    FROM Expertise
    GROUP BY Expertise
    ORDER BY cnt DESC
), T2 AS (
   SELECT ROW_NUMBER() OVER (ORDER BY cnt DESC) AS rn, Expertise
   FROM T1
)
SELECT (SELECT Expertise FROM T2 WHERE rn = 1) + ',' + 
       (SELECT Expertise FROM T2 WHERE rn = 2) + ',' +
       (SELECT Expertise FROM T2 WHERE rn = 3)

Результат:

dfdf,.NEt,fgfg

Answer 3

Неважно, я уже понял, вот ответ

SELECT DISTINCT
aId, 
EmpNames = substring( ( SELECT Top 3 ', ' + Expertise
FROM Expertise e2 
WHERE e2.aId = e1.aId FOR XML path(''), elements  
),2,500) 
FROM Expertise e1