Я создал представление MySQL, используя UNION ALL
из двух таблиц, чтобы получить одинаковые имена столбцов для одинаковых данных в этих таблицах (т.е. tbl1.author2 AS translator
... tbl2.translator AS translator
) и т. Д. когда я пытаюсь выбрать что-то из этого представления, половина данных получается как BLOB
вместо исходного значения.
Определение вида:
SELECT e.id AS prod_id,
e.price_vat AS price_vat,
e.product AS title,
e.authors AS author,
e.isbn AS isbn,
e.ean AS ean,
e.page_count AS page_count,
e.publishers AS publishers,
e.issue_year AS issue_year,
'e' AS type
FROM ama_euromedia_products AS e
UNION ALL
SELECT
k.publishers AS publishers,
DATE_FORMAT(k.publication_date, '%Y') AS issue_year,
k.ean AS ean,
k.number_of_pages AS page_count,
k.author AS author,
k.isbn AS isbn,
k.title_full AS title,
k.price_amount AS price_vat,
k.internal AS prod_id,
'k' AS type
FROM ama_kosmas_products AS k
Таблица определений:
CREATE TABLE `ama_euromedia_products` (
`id` int(9) NOT NULL,
`product` text COLLATE utf8_czech_ci NOT NULL,
`isbn` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`authors` text COLLATE utf8_czech_ci,
`publishers` text COLLATE utf8_czech_ci,
`price` float(9,0) DEFAULT NULL,
`price_vat` float(9,0) DEFAULT NULL,
`vat` int(3) DEFAULT NULL,
`availability` tinyint(1) DEFAULT NULL,
`genres` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`ean` bigint(14) DEFAULT NULL,
`page_count` int(7) DEFAULT NULL,
`issue_year` int(4) DEFAULT NULL,
`supply_date` timestamp NULL DEFAULT NULL,
`width` int(7) DEFAULT NULL,
`height` int(7) DEFAULT NULL,
`weight` int(7) DEFAULT NULL,
`binding` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`long_v` text COLLATE utf8_czech_ci,
`short` text COLLATE utf8_czech_ci,
`imgurl` text COLLATE utf8_czech_ci,
`is_preliminary` tinyint(1) DEFAULT NULL,
`stack_date` timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP,
`invoice_only` tinyint(1) DEFAULT NULL,
`new` tinyint(1) DEFAULT NULL,
`sale` tinyint(1) DEFAULT NULL,
`return_v` tinyint(1) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `indexy` (`id`,`isbn`,`genres`,`ean`,`issue_year`,`supply_date`,`stack_date`,`new`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_czech_ci;
CREATE TABLE `ama_kosmas_products` (
`id` int(7) NOT NULL AUTO_INCREMENT,
`internal` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`isbn` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`ean` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`contained_items` text COLLATE utf8_czech_ci,
`title_original` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`title_full` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`subtitle` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`other_text` text COLLATE utf8_czech_ci,
`languages` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`author` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`illustrator` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`translator` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`number_of_pages` int(7) DEFAULT NULL,
`subject_scheme_name` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`subject_code` int(7) DEFAULT NULL,
`subject_heading_text` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`media_file_label` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`media_file_thumbnail` varchar(255) COLLATE utf8_czech_ci DEFAULT NULL,
`publishers` text COLLATE utf8_czech_ci,
`publishing_status` tinyint(2) DEFAULT NULL,
`publication_date` timestamp NULL DEFAULT NULL,
`product_availability` tinyint(2) DEFAULT NULL,
`on_hand` int(7) DEFAULT NULL,
`on_order` int(7) DEFAULT NULL,
`price_amount` int(7) DEFAULT NULL,
`price_tax_rate_code` varchar(1) COLLATE utf8_czech_ci DEFAULT NULL,
`price_tax_rate_percent` tinyint(2) DEFAULT NULL,
`price_tax_amount` int(7) DEFAULT NULL,
`price_taxable_amount` int(7) DEFAULT NULL,
`reissue_date` timestamp NULL DEFAULT NULL,
`invoice_only` tinyint(1) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `internal` (`internal`)
) ENGINE=MyISAM AUTO_INCREMENT=43341 DEFAULT CHARSET=utf8 COLLATE=utf8_czech_ci;
Есть идеи, почему это может быть?