Регулярное выражение для соответствия пути в C # - PullRequest
6 голосов
/ 18 октября 2011

Я новичок с регулярными выражениями. Мне нужно извлечь путь из следующих строк:

XXXX       c:\mypath1\test
YYYYYYY             c:\this is other path\longer
ZZ        c:\mypath3\file.txt

Мне нужно реализовать метод, который возвращает путь к данной строке. Первый столбец - это слово с 1 или более символами, никогда не бывает пустым, второй столбец - это путь. Разделитель может содержать 1 или несколько пробелов, одну или несколько вкладок или оба.

Ответы [ 3 ]

7 голосов
/ 18 октября 2011

Звучит так, будто ты просто хочешь

string[] bits = line.Split(new char[] { '\t', ' ' }, 2,
                           StringSplitOptions.RemoveEmptyEntries);
// TODO: Check that bits really has two entries
string path = bits[1];

(Предполагается, что первый столбец никогда не содержит пробелов или табуляций.)

РЕДАКТИРОВАТЬ: Как регулярное выражение вы, вероятно, можете просто сделать:

Regex regex = new Regex(@"^[^ \t]+[ \t]+(.*)$");

Пример кода:

using System;
using System.Text.RegularExpressions;

class Program
{
    static void Main(string[] args)
    {
        string[] lines = 
        {
            @"XXXX       c:\mypath1\test",
            @"YYYYYYY             c:\this is other path\longer",
            @"ZZ        c:\mypath3\file.txt"
        };

        foreach (string line in lines)
        {
            Console.WriteLine(ExtractPathFromLine(line));
        }
    }

    static readonly Regex PathRegex = new Regex(@"^[^ \t]+[ \t]+(.*)$");

    static string ExtractPathFromLine(string line)
    {
        Match match = PathRegex.Match(line);
        if (!match.Success)
        {
            throw new ArgumentException("Invalid line");
        }
        return match.Groups[1].Value;
    }    
}
5 голосов
/ 18 октября 2011
StringCollection resultList = new StringCollection();
try {
    Regex regexObj = new Regex(@"(([a-z]:|\\\\[a-z0-9_.$]+\\[a-z0-9_.$]+)?(\\?(?:[^\\/:*?""<>|\r\n]+\\)+)[^\\/:*?""<>|\r\n]+)");
    Match matchResult = regexObj.Match(subjectString);
    while (matchResult.Success) {
        resultList.Add(matchResult.Groups[1].Value);
        matchResult = matchResult.NextMatch();
    } 
} catch (ArgumentException ex) {
    // Syntax error in the regular expression
}

Разбивка:

@"
(                             # Match the regular expression below and capture its match into backreference number 1
   (                             # Match the regular expression below and capture its match into backreference number 2
      |                             # Match either the regular expression below (attempting the next alternative only if this one fails)
         [a-z]                         # Match a single character in the range between “a” and “z”
         :                             # Match the character “:” literally
      |                             # Or match regular expression number 2 below (the entire group fails if this one fails to match)
         \\                            # Match the character “\” literally
         \\                            # Match the character “\” literally
         [a-z0-9_.$]                   # Match a single character present in the list below
                                          # A character in the range between “a” and “z”
                                          # A character in the range between “0” and “9”
                                          # One of the characters “_.$”
            +                             # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
         \\                            # Match the character “\” literally
         [a-z0-9_.$]                   # Match a single character present in the list below
                                          # A character in the range between “a” and “z”
                                          # A character in the range between “0” and “9”
                                          # One of the characters “_.$”
            +                             # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
   )?                            # Between zero and one times, as many times as possible, giving back as needed (greedy)
   (                             # Match the regular expression below and capture its match into backreference number 3
      \\                            # Match the character “\” literally
         ?                             # Between zero and one times, as many times as possible, giving back as needed (greedy)
      (?:                           # Match the regular expression below
         [^\\/:*?""<>|\r\n]             # Match a single character NOT present in the list below
                                          # A \ character
                                          # One of the characters “/:*?""<>|”
                                          # A carriage return character
                                          # A line feed character
            +                             # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
         \\                            # Match the character “\” literally
      )+                            # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
   )
   [^\\/:*?""<>|\r\n]             # Match a single character NOT present in the list below
                                    # A \ character
                                    # One of the characters “/:*?""<>|”
                                    # A carriage return character
                                    # A line feed character
      +                             # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
"
0 голосов
/ 18 октября 2011

Regex Tester - это хороший сайт для быстрого тестирования Regex.

Regex.Matches(input, "([a-zA-Z]*:[\\[a-zA-Z0-9 .]*]*)");
...