Сортировка ответа JSON по фамилии - PullRequest
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Сортировка ответа JSON по фамилии

0 голосов
/ 06 мая 2011 
{"PatientSearchResult":{"Patient":[{"AccountBalanceCalcMethod":2,"AlternatePatientID":0,"AssignmentOfBenifits":0,"CellPhoneNumber1":null,"CellPhoneNumber2":null,"Citizenship":0,"Credential":0,"DateOfBirth":null,"Deceased":0,"DeceasedDate":"\/Date(-62135578800000-0500)\/","DoesPatientHaveResidentProof":false,"DriversLicenseNumber":null,"DriversLicenseState":0,"EmailAddress1":null,"EmailAddress2":null,"Enabled":false,"Ethnicity":0,"Firstname":"2914 FirstName","FullName":"2914 FirstName 2914 LastName","Gender":2,"GuarantorID":0,"IsFinancialRisk":false,"IsPatient":false,"LastName":"2914 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Это мой ответ JSON, как бы я его отсортировал.Что я пытался

var data = eval(PatientSearchResponse);
var results = data['results'];

PatientSearchResponse.SortByName(results);

function SortByName(x,y) {      
  return ((x.LastName == y.LastName) ? 0 : ((x.LastName > y.LastName) ? 1 : -1 ));    
}

Не сработало.

Ответы [ 2 ]

2 голосов
/ 06 мая 2011

Несколько проблем здесь;results не существует в ответе JSON, который вы дали, а SortByName является функцией, доступной для текущей области, но не является членом PatientSearchResponse.

Предположительно, вы хотите что-то вроде этого: 

var data = eval(PatientSearchResponse); // use JSON.parse if available
var results = data['PatientSearchResult'];

// Call the `sort` method, passing SortByName as the first argument
results.Patient.sort(SortByName);

function SortByName(x,y) {      
  return ((x.LastName == y.LastName) ? 0 : ((x.LastName > y.LastName) ? 1 : -1 ));    
}
0 голосов
/ 06 мая 2011

Я не знаю, какой сценарий на стороне сервера вы используете, если его PHP, то

Попробуйте unserialize , это приведет к десериализации объекта json в массив (только если ваш формат данных json правильный).

Затем вы можете отсортировать массив, используя функции сортировки массива.

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