Я создаю простой курсор, который выбирает все записи из таблицы и для каждой записи проверяет условие в другой таблице и обновляет первую таблицу.
Для этого я использую курсор.
Этот курсор не работает. Я проверил записи доступны. Кажется, он вообще не попадает в курсор
ALTER PROCEDURE [dbo].[updatetimecardlineitemsabc]
-- Add the parameters for the stored procedure here
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
-- Insert statements for procedure here
SELECT *
INTO #tctemp
FROM timecardlineitem
DECLARE @records_size INT
DECLARE @ctr INT
SET @ctr=0
SET @records_size = 0
DECLARE @Id VARCHAR(30)
DECLARE @project VARCHAR(30)
DECLARE @consultant VARCHAR(30)
DECLARE @ass_cons VARCHAR(30)
DECLARE @mondate DATE
DECLARE @sundate DATE
DECLARE @acId VARCHAR(30)
DECLARE @count INT
DECLARE @ct INT
PRINT( 'hello' )
SELECT @ct = COUNT(*)
FROM timecardlineitem
WHERE assigned_consultant__c IS NULL
PRINT( '@ct is .....' + CONVERT(VARCHAR(20), @ct) )
DECLARE cursor_Timecard_Line_Item CURSOR FOR
SELECT id,
project__c,
consultantId__c,
assigned_consultant__c,
MONDAY_DATE__C,
SUNDAY_DATE__C
FROM timecardlineitem
WHERE assigned_consultant__c IS NULL
OPEN cursor_Timecard_Line_Item
FETCH cursor_Timecard_Line_Item
INTO @Id, @project, @consultant,
@ass_cons,@mondate, @sundate
PRINT('@id,@project,@consultant......'+@id+'-----'+@project+'-----'+@ass_cons+
'-----'+convert(varchar,@mondate)+'-----'+convert(varchar,@sundate))
WHILE @@FETCH_STATUS = 0
BEGIN
SELECT @acId = ID
FROM assignedcons
WHERE Project__c = @project
AND Contact__c = @consultant
AND ( Start_Date__c <= @sundate
OR Start_Date__c = NULL )
AND ( End_Date__c >= @mondate
OR End_Date__c = NULL )
UPDATE timecardlineitem
SET assigned_consultant__c = @acId
WHERE id = @Id
FETCH cursor_Timecard_Line_Item
INTO @Id, @project, @consultant,
@ass_cons,@mondate, @sundate
END
CLOSE cursor_Timecard_Line_Item
DEALLOCATE cursor_Timecard_Line_Item
END
Это просто печатает привет
@ct is ..... 483
Есть 483 записи
Он не печатает операторы print внутри выборки. Я знаю, что делаю что-то очень глупое. Просто не в состоянии идентифицировать это
Редактировать: это то, что нужно
У меня есть 2 таблицы
- timecardlineitem
- assigned_consultant__c
Вот структура timecardlineitem
[ID] [varchar](50) NULL,
[ISDELETED] [varchar](50) NULL,
[NAME] [varchar](50) NULL,
[CREATEDDATE] [varchar](50) NULL,
[CREATEDBYID] [varchar](50) NULL,
[LASTMODIFIEDDATE] [varchar](50) NULL,
["LASTMODIFIEDBYID"] [varchar](50) NULL,
[SYSTEMMODSTAMP] [varchar](50) NULL,
[LASTACTIVITYDATE] [varchar](50) NULL,
[TIMECARD__C] [varchar](50) NULL,
[ASSIGNED_CONSULTANT_EXISTS__C] [varchar](50) NULL,
[FRIDAY_DATE__C] [varchar](50) NULL,
[FRIDAY_HOURS__C] [varchar](50) NULL,
[MONDAY_DATE__C] [varchar](50) NULL,
[MONDAY_HOURS__C] [varchar](50) NULL,
[PROJECT_END_DATE__C] [varchar](50) NULL,
[PROJECT_NAME__C] [varchar](50) NULL,
[PROJECT_START_DATE__C] [varchar](50) NULL,
[PROJECT__C] [varchar](50) NULL,
[SATURDAY_DATE__C] [varchar](50) NULL,
[SATURDAY_HOURS__C] [varchar](50) NULL,
[STATUS__C] [varchar](50) NULL,
[SUNDAY_DATE__C] [varchar](50) NULL,
[SUNDAY_HOURS__C] [varchar](50) NULL,
[THURSDAY_DATE__C] [varchar](50) NULL,
[THURSDAY_HOURS__C] [varchar](50) NULL,
[TOTAL_HOURS__C] [varchar](50) NULL,
[TUESDAY_DATE__C] [varchar](50) NULL,
[TUESDAY_HOURS__C] [varchar](50) NULL,
[WEDNESDAY_DATE__C] [varchar](50) NULL,
[WEDNESDAY_HOURS__C] [varchar](50) NULL,
[BILLABLE_HOURS__C] [varchar](50) NULL,
[CLIENT_NAME__C] [varchar](50) NULL,
[TOTAL_EXPECTED_HOURS__C] [varchar](50) NULL,
[PROJECT_TYPE__C] [varchar](50) NULL,
[PROFESSIONAL_CHECKBOX__C] [varchar](50) NULL,
[DAY_CHARGE__C] [varchar](50) NULL,
[UTILIZATION_NO_DAY_CHARGE__C] [varchar](50) NULL,
[MONDAY_DAY_CHARGE__C] [varchar](50) NULL,
[TUESDAY_DAY_CHARGE__C] [varchar](50) NULL,
[WEDNESDAY_DAY_CHARGE__C] [varchar](50) NULL,
[THURSDAY_DAY_CHARGE__C] [varchar](50) NULL,
[FRIDAY_DAY_CHARGE__C] [varchar](50) NULL,
[SATURDAY_DAY_CHARGE__C] [varchar](50) NULL,
[SUNDAY_DAY_CHARGE__C] [varchar](50) NULL,
[UTILIZATION_DAY_CHARGE__C] [varchar](50) NULL,
[UTILIZATION_DAYS__C] [varchar](50) NULL,
[CONSULTANT_NAME__C] [varchar](50) NULL,
[BILLING_WEEKLY_TARGET__C] [varchar](50) NULL,
[UTILIZATION__C] [varchar](50) NULL,
[HOURS_REMAINING_ON_PROJECT__C] [varchar](50) NULL,
[PROJECT_OWNER__C] [varchar](50) NULL,
[CONSULTANTID__C] [varchar](50) NULL,
[ASSIGNED_CONSULTANT__C] [varchar](50) NULL
Вот структура [assigncons]
[ID] [varchar](50) NULL,
[ISDELETED] [varchar](50) NULL,
[NAME] [varchar](50) NULL,
[CREATEDDATE] [varchar](50) NULL,
[CREATEDBYID] [varchar](50) NULL,
[LASTMODIFIEDDATE] [varchar](50) NULL,
[LASTMODIFIEDBYID] [varchar](50) NULL,
[SYSTEMMODSTAMP] [varchar](50) NULL,
[LASTACTIVITYDATE] [varchar](50) NULL,
[PROJECT__C] [varchar](50) NULL,
[CONTACT__C] [varchar](50) NULL,
[APPROVING_MANAGER__C] [varchar](50) NULL,
[C85_EMAIL_ADDRESS__C] [varchar](50) NULL,
[C85_PROJECT_LEAD__C] [varchar](50) NULL,
[CURRENT_STATUS_FORMULA__C] [varchar](50) NULL,
[CURRENT_STATUS__C] [varchar](50) NULL,
[DAILY_CHARGE_RATE_OF_CONSULTANT__C] [varchar](50) NULL,
[END_DATE__C] [varchar](50) NULL,
[LEAVE_STATUS__C] [varchar](50) NULL,
[LEAVE_TYPE__C] [varchar](50) NULL,
[LEAVES_AVAILABLE__C] [varchar](50) NULL,
[NOTES__C] [varchar](50) NULL,
[PROJECT_ROLE_TITLE__C] [varchar](50) NULL,
[REMAINING_YEAR_FREE_DAYS_FORMULA__C] [varchar](50) NULL,
[REMAINING_YEAR_FREE_DAYS__C] [varchar](50) NULL,
[START_DATE__C] [varchar](50) NULL,
[TOTAL_LEAVES_APPLIED__C] [varchar](50) NULL,
[TOTAL_PO_VALUE_FOR_CONSULTANT__C] [varchar](50) NULL,
[UNIQUE_PARAMETER__C] [varchar](50) NULL,
[YEAR_END__C] [varchar](50) NULL,
[ASSIGNED_DAYS_TO_CONSULTANT__C] [varchar](50) NULL,
[CONSULTANT_DAY_COST__C] [varchar](50) NULL,
[MARGIN_ACHIEVED__C] [varchar](50) NULL,
[OVERTIME_ALLOWED__C] [varchar](50) NULL,
[CLIENT_NAME__C] [varchar](50) NULL,
[SUB_TOTAL__C] [varchar](50) NULL,
[BILLABLE_HOURS__C] [varchar](50) NULL,
[CONSULTANT_DAY_COST_STAMPED__C] [varchar](50) NULL,
[TOTAL_HOURS_BOOKED_APPROVED__C] [varchar](50) NULL,
[LAST_TIMECARD_DATE__C] [varchar](50) NULL,
[TOTAL_CHARGES_INCURRED__C] [varchar](50) NULL,
[DAYS_APPROVED__C] [varchar](50) NULL,
[STATUS__C] [varchar](50) NULL,
[ID_WITH_LINK__C] [varchar](50) NULL,
[TOTAL_HOURS_REMAINING_ON_PROJECT__C] [varchar](50) NULL,
[NOMINAL_CODE__C] [varchar](50) NULL
В timecardlineitem есть несколько записей, которые имеют нулевые значения в поле ASSIGNED_CONSULTANT__C
Для тех записей, которые имеют нулевое значение, мне нужно искать идентификатор в назначенном
т.е. мне нужно будет получить первую запись от timecardlineitem, выполнить поиск по назначенным элементам, у которых одинаковые идентификатор проекта и консультанта, а дата начала - <= SUNDAY_DATE__C, а конечная дата -> = MONDAY_DATE__C
SELECT ID
FROM assignedcons
WHERE Project__c = @project // @project is the project__c from timecardlineitem
AND Contact__c = @consultant // @consultant is the CONSULTANTID__C from timecardlineitem
AND ( Start_Date__c <= @sundate //@sundate is the SUNDAY_DATE__C from timecardlineitem
OR Start_Date__c = NULL )
AND ( End_Date__c >= @mondate //@sundate is the monday_DATE__C from timecardlineitem
OR End_Date__c = NULL )
ID ASSIGNED_CONSULTANT__C project__c CONSULTANTID__C SUNDAY_DATE__C monday_DATE__C
1 null pjA CS1 16-Oct-2011 09-oct-2011
2 null pjB CS2 16-Oct-2011 09-oct-2011
Assigned consultant project__c Contact__c startDate Enddate
AC-001 CS1 pjA cs1 09-oct-2011 16-oct-2011
ASSIGNED_CONSULTANT__C должен содержать AC-001 для timecardlineitem с идентификатором 1