По моему опыту, FileStream, открытый с помощью FileOptions.DeleteOnClose, нельзя открыть, передав путь к файлу другому FileStream независимо от значения FileShare.
Когда вы владеете всем кодом (явно не ваш случай, извините) DuplicateHandle можно использовать для открытия файла DeleteOnClose несколько раз, даже из разных процессов.
Вот пример кода для .NET 4.5.1.
using System;
using System.Diagnostics;
using System.IO;
using System.Runtime.InteropServices;
using System.Text;
using System.Windows.Forms;
using Microsoft.Win32.SafeHandles;
namespace Example
{
public static class DuplicatedHandleExample
{
[DllImport("kernel32.dll")]
private static extern bool DuplicateHandle(
SafeFileHandle hSourceProcessHandle,
IntPtr hSourceHandle,
SafeFileHandle hTargetProcessHandle,
out SafeFileHandle lpTargetHandle,
UInt32 dwDesiredAccess,
bool bInheritHandle,
UInt32 dwOptions);
[DllImport("kernel32.dll")]
private static extern SafeFileHandle OpenProcess(
UInt32 dwDesiredAccess,
bool bInheritHandle,
int dwProcessId);
private const UInt32 PROCESS_DUP_HANDLE = 0x0040;
private const UInt32 DUPLICATE_SAME_ACCESS = 0x0002;
public static void CreateFileInProcessA()
{
try
{
// open new temp file with FileOptions.DeleteOnClose
string tempFilePath = Path.Combine(Path.GetTempPath(), Guid.NewGuid().ToString("D"));
using (FileStream fs = new FileStream(tempFilePath, FileMode.CreateNew,
FileAccess.ReadWrite, FileShare.Read | FileShare.Write | FileShare.Delete,
4096, FileOptions.DeleteOnClose))
{
// put a message in the temp file
fs.Write(new[] { (byte)'h', (byte)'i', (byte)'!' }, 0, 3);
fs.Flush();
// put our process ID and file handle on clipboard
string data = string.Join(",",
Process.GetCurrentProcess().Id.ToString(),
fs.SafeFileHandle.DangerousGetHandle().ToString());
Clipboard.SetData(DataFormats.UnicodeText, data);
// show messagebox (while holding file open!) and wait for user to click OK
MessageBox.Show("Temp File opened. Process ID and File Handle copied to clipboard. Click OK to close temp file.");
}
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
public static void OpenFileInProcessB()
{
try
{
// get process ID and file handle from clipboard
string data = (string)Clipboard.GetData(DataFormats.UnicodeText);
string[] dataParts = data.Split(',');
int sourceProcessId = int.Parse(dataParts[0]);
IntPtr sourceFileHandle = new IntPtr(Int64.Parse(dataParts[1]));
// get handle to target process
using (SafeFileHandle sourceProcessHandle =
OpenProcess(PROCESS_DUP_HANDLE, false, sourceProcessId))
{
// get handle to our process
using (SafeFileHandle destinationProcessHandle =
OpenProcess(PROCESS_DUP_HANDLE, false, Process.GetCurrentProcess().Id))
{
// duplicate handle into our process
SafeFileHandle destinationFileHandle;
DuplicateHandle(sourceProcessHandle, sourceFileHandle,
destinationProcessHandle, out destinationFileHandle,
0, false, DUPLICATE_SAME_ACCESS);
// get a FileStream wrapper around it
using (FileStream fs = new FileStream(destinationFileHandle, FileAccess.ReadWrite, 4096))
{
// read file contents
fs.Position = 0;
byte[] buffer = new byte[100];
int numBytes = fs.Read(buffer, 0, 100);
string message = Encoding.ASCII.GetString(buffer, 0, numBytes);
// show messagebox (while holding file open!) and wait for user to click OK
MessageBox.Show("Found this message in file: " + message + Environment.NewLine +
"Click OK to close temp file");
}
}
}
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
}
}