SQL-запрос для генерации матрицы, такой как вывод запросов к связанной таблице в SQL Server - PullRequest
9 голосов
/ 07 марта 2011

У меня есть три таблицы:
Продукт

ProductID   ProductName  
1           Cycle  
2           Scooter  
3           Car  

Клиент

CustomerID  CustomerName  
101         Ronald  
102         Michelle  
103         Armstrong  
104         Schmidt  
105         Peterson   

уже

TID   ProductID CustomerID TranDate   Amount  
10001 1         101        01-Jan-11  25000.00  
10002 2         101        02-Jan-11  98547.52  
10003 1         102        03-Feb-11  15000.00  
10004 3         102        07-Jan-11  36571.85  
10005 2         105        09-Feb-11  82658.23  
10006 2         104        10-Feb-11  54000.25  
10007 3         103        20-Feb-11  80115.50  
10008 3         104        22-Feb-11  45000.65  

Я написал запрос для группировки транзакций следующим образом:

SELECT P.ProductName AS Product,  
       C.CustName AS Customer,  
       SUM(T.Amount) AS Amount  
FROM   Transactions AS T  
       INNER JOIN Product AS P  
            ON  T.ProductID = P.ProductID  
       INNER JOIN Customer AS C  
            ON  T.CustomerID = C.CustomerID  
WHERE T.TranDate BETWEEN '2011-01-01' AND '2011-03-31'   
GROUP BY  
       P.ProductName,  
       C.CustName  
ORDER BY  
       P.ProductName  

, который дает такой результат:

Product Customer   Amount  
Car     Armstrong  80115.50  
Car     Michelle   36571.85  
Car     Schmidt    45000.65  
Cycle   Michelle   15000.00  
Cycle   Ronald     25000.00  
Scooter Peterson   82658.23  
Scooter Ronald     98547.52  
Scooter Schmidt    54000.25  

IНужен результат запроса в форме MATRIX, например:

Customer  |------------ Amounts ---------------         
Name      |Car      Cycle     Scooter  Totals
Armstrong  80115.50 0.00      0.00     80115.50  
Michelle   36571.85 15000.00  0.00     51571.85  
Ronald     0.00     25000.00  98547.52 123547.52  
Peterson   0.00     0.00      82658.23 82658.23  
Schmidt    45000.65 0.00      54000.25 99000.90  

Пожалуйста, помогите мне получить вышеуказанный результат в SQL Server 2005. Использование многократных представлений или даже временных таблиц мне подходит.

Ответы [ 2 ]

12 голосов
/ 07 марта 2011

Вы можете использовать оператор SQL Server PIVOT

SELECT  *
FROM    (
          SELECT  P.ProductName
                  , C.CustName
                  , T.Amount
          FROM    Transactions AS T  
                  INNER JOIN Product AS P ON  T.ProductID = P.ProductID  
                  INNER JOIN Customer AS C ON  T.CustomerID = C.CustomerID  
          WHERE   T.TranDate BETWEEN '2011-01-01' AND '2011-03-31'   
        ) s
PIVOT   (SUM(Amount) FOR ProductName IN ([Car], [Cycle], [Scooter])) pvt

Тестовые данные

;WITH q AS (
  SELECT  [Product] = 'Car', [Customer] = 'Armstrong', [Amount] = 80115.50
  UNION ALL SELECT 'Car', 'Michelle', 36571.85  
  UNION ALL SELECT 'Car', 'Schmidt', 45000.65  
  UNION ALL SELECT 'Cycle', 'Michelle', 15000.00  
  UNION ALL SELECT 'Cycle', 'Ronald', 25000.00  
  UNION ALL SELECT 'Scooter', 'Peterson', 82658.23  
  UNION ALL SELECT 'Scooter', 'Ronald', 98547.52  
  UNION ALL SELECT 'Scooter', 'Schmidt', 54000.25  
)
SELECT  Customer
        , Car = ISNULL(Car, 0)
        , Cycle = ISNULL(Cycle, 0)
        , Scooter = ISNULL(Scooter, 0)
        , Total = ISNULL(Car, 0) + ISNULL(Cycle, 0) + ISNULL(Scooter, 0)
FROM    (
          SELECT  *
          FROM    q
        ) s
PIVOT   (SUM(Amount) FOR Product IN ([Car], [Cycle], [Scooter])) pvt

Выход

Customer   Car       Cycle     Scooter   Total
Armstrong  80115.50  0.00      0.00      80115.50
Michelle   36571.85  15000.00  0.00      51571.85
Peterson   0.00      0.00      82658.23  82658.23
Ronald     0.00      25000.00  98547.52  123547.52
Schmidt    45000.65  0.00      54000.25  99000.90
0 голосов
/ 25 сентября 2013
create table #Product (ProductID   int,ProductName  varchar(15))
insert into #Product values (1,'Cycle')
insert into #Product values (2,'Scooter')
insert into #Product values (3,'Car')

create table #Customer (CustomerID   int, CustomerName  varchar(30))
insert into #Customer values (101,'Ronald')
insert into #Customer values (102,'Michelle')
insert into #Customer values (103,'Armstrong')
insert into #Customer values (104,'Schmidt')
insert into #Customer values (105,'Peterson')

create table #Transactions (TID int,ProductID int,CustomerID int, TranDate smalldatetime,Amount decimal(18,2))
insert into #Transactions values (10001,1,101,'01-Jan-11',25000.00)
insert into #Transactions values (10002,2,101,'02-Jan-11',98547.52)
insert into #Transactions values (10003,1,102,'03-Feb-11',15000.00)
insert into #Transactions values (10004,3,102,'07-Jan-11',36571.85)
insert into #Transactions values (10005,2,105,'09-Feb-11',82658.23)
insert into #Transactions values (10006,2,104,'10-Feb-11',54000.25)
insert into #Transactions values (10007,3,103,'20-Feb-11',80115.50)
insert into #Transactions values (10008,3,104,'22-Feb-11',45000.65)

with temp as 
(
select cus.CustomerName,pro.ProductName, sum(trans.Amount) as Amount from #Transactions as trans
inner join #Customer as cus on trans.CustomerID = cus.CustomerID
inner join #Product as pro on trans.ProductID = pro.ProductID
group by cus.CustomerName,pro.ProductName
)

select CustomerName,isnull([Car],0)Car, isnull([Cycle],0)Cycle,isnull([Scooter],0) as Scooter, isnull([Car],0)+isnull([Cycle],0)+isnull([Scooter],0)as Total  from temp
pivot (
sum(Amount) for ProductName in ([Cycle],[Scooter],[Car])
)pot*
...