Расчет рабочих часов в SQL

Question

Мне нужно рассчитать рабочие часы между датами.

Мне нужно исключить следующие из этих часов.

1. В нерабочее время (с 18:00 до 9:00)
2. Выходные
3. Праздники

В праздничные дни у меня есть таблица HOLIDAYS as

DATE        NAME
----------------------------------
2012-01-02  New Year's Day
2012-04-06  Good Friday
2012-04-09  Easter Monday

Примечания:1. У меня есть часы начала и окончания («2012/03/15 14:00» до «2012/03/22 17:30»).2. Я использую Sql Server 2005, поэтому у меня нет дат даты или времени.

Answer 1

Попробуйте это.

DECLARE @start_date DATETIME 
DECLARE @stop_date DATETIME 
DECLARE @days INT

SELECT @start_date = '2012/03/15 14:00', @stop_date = '2012/03/22 17:30'

SELECT @days = DATEDIFF(DAY, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME), CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)) + 1

;WITH CTE_ALL_DAYS AS (
    SELECT TOP (@days) 
        DATEADD(DAY, rn, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME)) AS dt
    FROM (
        SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 1)) - 1 AS rn
        FROM master.sys.all_columns AS a
        CROSS JOIN master.sys.all_columns AS b
        ) AS tally
)
SELECT SUM(
        CASE
            WHEN dt = CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME) THEN 
                CASE 
                    WHEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) > 9 THEN 9
                    WHEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) > 0 THEN DATEDIFF(HOUR, @start_date, DATEADD(HOUR, 18, CAST(FLOOR(CAST(@start_date AS FLOAT)) AS DATETIME))) 
                    ELSE 0 
                END
            WHEN dt = CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME) THEN 
                CASE 
                    WHEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) > 9 THEN 9
                    WHEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) > 0 THEN DATEDIFF(HOUR, DATEADD(HOUR, 9, CAST(FLOOR(CAST(@stop_date AS FLOAT)) AS DATETIME)), @stop_date) 
                    ELSE 0 
                END 
            ELSE 9      
        END
    )
FROM CTE_ALL_DAYS   
WHERE 
    NOT DATEPART(weekday, dt) IN (1, 7)
    AND NOT dt IN (SELECT [DATE] FROM HOLIDAYS)