Я старался изо всех сил, чтобы этот скрипт работал, и я просто не могу понять, что я делаю неправильно. Я очень новичок в PHP и Javascript, и я пытаюсь изменить скрипт, который я нашел в Интернете, чтобы получить каскадные выпадающие списки на моем сайте. Это довольно простой скрипт, который, к сожалению, не использует AJAX, поэтому он требует обновления страницы, но если у меня возникают трудности с этим, я не думаю, что мне следует переходить к AJAX. Проблема, с которой я столкнулся, заключается в том, что скрипт должен сделать мой выбор из меню одним флешкой, когда страница обновляется, но всегда сбрасывается обратно в SELECT ONE, по умолчанию. Он работает в оригинальном сценарии, но я сделал немало модификаций, поэтому я не могу понять, почему мой не залипает. Оригинальный скрипт:
<?php
//***************************************
// This is downloaded from www.plus2net.com //
/// You can distribute this code with the link to www.plus2net.com ///
// Please don't remove the link to www.plus2net.com ///
// This is for your learning only not for commercial use. ///////
//The author is not responsible for any type of loss or problem or damage on using this script.//
/// You can use it at your own risk. /////
//*****************************************
$dbservertype='mysql';
$servername='localhost';
// username and password to log onto db server
$dbusername='';
$dbpassword='';
// name of database
$dbname='dd';
////////////////////////////////////////
////// DONOT EDIT BELOW /////////
///////////////////////////////////////
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword)
{
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());
}
//////// End of connecting to database ////////
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].value;
self.location='dd.php?cat=' + val ;
}
</script>
</head>
<body>
<?
/*
If register_global is off in your server then after reloading of the page to get the value of cat from query string we have to take special care.
To read more on register_global visit.
http://www.plus2net.com/php_tutorial/register-globals.php
*/
@$cat=$_GET['cat']; // Use this line or below line if register_global is off
if(strlen($cat) > 0 and !is_numeric($cat)){ // to check if $cat is numeric data or not.
echo "Data Error";
exit;
}
//@$cat=$HTTP_GET_VARS['cat']; // Use this line or above line if register_global is off
///////// Getting the data from Mysql table for first list box//////////
$quer2=mysql_query("SELECT DISTINCT category,cat_id FROM category order by category");
///////////// End of query for first list box////////////
/////// for second drop down list we will check if category is selected else we will display all the subcategory/////
if(isset($cat) and strlen($cat) > 0){
$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory where cat_id=$cat order by subcategory");
}else{$quer=mysql_query("SELECT DISTINCT subcategory FROM subcategory order by subcategory"); }
////////// end of query for second subcategory drop down list box ///////////////////////////
echo "<form method=post name=f1 action='dd-check.php'>";
/// Add your form processing page address to action in above line. Example action=dd-check.php////
////////// Starting of first drop downlist /////////
echo "<select name='cat' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($noticia2 = mysql_fetch_array($quer2)) {
if($noticia2['cat_id']==@$cat)
{echo "<option selected value='$noticia2[cat_id]'>$noticia2[category]</option>"."<BR>";}
else{echo "<option value='$noticia2[cat_id]'>$noticia2[category]</option>";}
}
echo "</select>";
////////////////// This will end the first drop down list ///////////
////////// Starting of second drop downlist /////////
echo "<select name='subcat'><option value=''>Select one</option>";
while($noticia = mysql_fetch_array($quer)) {
echo "<option value='$noticia[subcategory]'>$noticia[subcategory]</option>";
}
echo "</select>";
////////////////// This will end the second drop down list ///////////
//// Add your other form fields as needed here/////
echo "<input type=submit value=Submit>";
echo "</form>";
?>
<center><a href='http://www.plus2net.com'>PHP SQL HTML free tutorials and scripts</a></center>
</body>
</html>
И мой сценарий:
<?php
$dbservertype='mysql';
$servername='localhost';
$dbusername='newuser';
$dbpassword='';
$dbname='supplydb';
connecttodb($servername,$dbname,$dbusername,$dbpassword);
function connecttodb($servername,$dbname,$dbuser,$dbpassword){
global $link;
$link=mysql_connect ("$servername","$dbuser","$dbpassword");
if(!$link){die("Could not connect to MySQL");}
mysql_select_db("$dbname",$link) or die ("could not open db".mysql_error());}
?>
<!doctype html public "-//w3c//dtd html 3.2//en">
<html>
<head>
<title>Multiple drop down list box from plus2net</title>
<SCRIPT language=JavaScript>
function reload(form){
var val=form.category.options[form.category.options.selectedIndex].text;
self.location='dd.php?cat=' + val ;
}
function reload2(form)
{
var val=form.cat.options[form.cat.options.selectedIndex].text;
var val2=form.subcat.options[form.subcat.options.selectedIndex].text;
self.location='dd.php?cat=' + val + '&cat2=' + val2 ;
console.log(val2);
}
</script>
</head>
<body>
<?
////// Grab Get after page refresh
$cat=$_GET['cat'];
$command="SELECT * FROM product_group WHERE type = 1";
$quer2 = mysql_query($command);
if(isset($cat) and strlen($cat) > 1){
$num = explode(' ',$cat);
$number = $num[0];
$strLen = strlen( $number );
for ( $i = 0; $i < $strLen; $i++ )
{$arr[] = $number{$i};}
$arr1 = $arr [0];
$arr2 = $arr [1];
$arr3 = $arr1.$arr2;
$command1="SELECT * FROM `product_group` WHERE `group` LIKE '".$arr3."%' AND type = '2'";
$quer = mysql_query($command1);
}
echo "<form method=post name=category action='dd-check.php'>";
///////////// Create First Drop Down Box
echo "<select name='category' onchange=\"reload(this.form)\"><option value=''>Select one</option>";
while($query = mysql_fetch_assoc($quer2)){
if($query['group']==$cat){
echo "<option selected value='$query[group]'>$query[group]</option>"."<BR>";}
else {echo "<option value='$query[group]'>$query[group]</option>";}
}
echo "</select>";
////////////// Create Second Drop Down Box
echo "<select name='subcat' onchange=\"reload2(this.form)\"><option value=''>Select one</option>";
while($query2 = mysql_fetch_array($quer)){
if($query2['group']==$cat2)
{echo "<option selected value='$query2[group]'>$query2[group]</option>"."<BR>";}
else {echo "<option value='$query2[group]'>$query2[group]</option>";}
}
echo "</select>";
echo "</form>";
print_r ($cat);
?>
</body>
</html>
Любая помощь в указании, где моя ошибка с головой, будет полезна. Заранее спасибо.