Вы можете использовать Process.Start метод:
class Program
{
static void Main()
{
var psi = new ProcessStartInfo
{
FileName = @"c:\work\test.exe",
Arguments = @"param1 param2",
UseShellExecute = false,
RedirectStandardOutput = true,
};
var process = Process.Start(psi);
if (process.WaitForExit((int)TimeSpan.FromSeconds(10).TotalMilliseconds))
{
var result = process.StandardOutput.ReadToEnd();
Console.WriteLine(result);
}
}
}