Вы можете попробовать:
<head runat="server">
<title></title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
$(document).ready(function(){
var options = {
beforeSend: function () {
$("#progress").show();
//clear everything
$("#bar").width('0%');
$("#message").html("");
$("#percent").html("0%");
},
uploadProgress: function (event, position, total, percentComplete) {
$("#bar").width(percentComplete + '%');
$("#percent").html(percentComplete + '%');
},
success: function () {
$("#bar").width('100%');
$("#percent").html('100%');
},
complete: function (response) {
$("#message").html("<font color='green'>" + response.responseText + "</font>");
},
error: function () {
$("#message").html("<font color='red'> ERROR: unable to upload files</font>");
}
};
$("#form1").ajaxForm(options);
});
</script>
<body>
<form id="form1" action="AjaxUploadFile.aspx" method="post" enctype="multipart/form-data" runat="server">
<div>
<input type="file" size="60" name="myfile" />
<input type="submit" value="Ajax File Upload" />
<div id="progress">
<div id="bar"></div>
<div id="percent">0%</div >
</div>
<br/>
<div id="message"></div>
</div>
</form>
код позади:
protected void Page_Load(object sender, EventArgs e)
{
HttpPostedFile file =null;
if (Request.Files.Count>0)
{
file = Request.Files[0];
file.SaveAs(Server.MapPath("~/UploadedFiles/")+file.FileName);
}
}