Как реализовать код для получения широты и долготы? - PullRequest
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Как реализовать код для получения широты и долготы?

0 голосов
/ 30 марта 2012

Привет всем, как получить значения широты и долготы местоположения? Я пытаюсь использовать приведенный ниже код, но получаю неправильный ответ, мне нужна ваша помощь для решения проблемы. 

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
NSString *city,*state,*zip;

city=@"Hyderabad";

state=@"Andrapradesh";

zip=@"22345";

address=city,state,zip;

NSLog(@"##########%@",address);

double latitude = 0, longitude = 0;

NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];

NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];

NSLog(@"333333%@",result);

if (result) {
NSScanner *scanner = [NSScanner scannerWithString:result];

NSLog(@"##########%@",scanner);

if ([scanner scanUpToString:@"\"lat\":" intoString:nil] && [scanner scanString:@"\"lat\":" intoString:nil]) {
[scanner scanDouble:&latitude];

NSLog(@"4444444%@",scanner);

NSLog(@"5555%@",latitude);

if ([scanner scanUpToString:@"\"lng\":" intoString:nil] && [scanner scanString:@"\"lng\":" intoString:nil]) {
[scanner scanDouble:&longitude];

NSLog(@"6666%@",scanner);

NSLog(@"7777%@",longitude);

}

}

}

CLLocationCoordinate2D center;

center.latitude = latitude;

NSLog(@"##########%@",latitude);

center.longitude = longitude;

return center;

}




333333 {

"results" : [

{

"address_components" : [

{

"long_name" : "Hyderabad",

"short_name" : "Hyderabad",

"types" : [ "locality", "political" ]

},

{

"long_name" : "Ranga Reddy",

"short_name" : "R.R. District",

"types" : [ "administrative_area_level_2", "political" ]

},

{

"long_name" : "Andhra Pradesh",

"short_name" : "Andhra Pradesh",

"types" : [ "administrative_area_level_1", "political" ]

},

{

"long_name" : "India",

"short_name" : "IN",

"types" : [ "country", "political" ]

}

],

"formatted_address" : "Hyderabad, Andhra Pradesh, India",

"geometry" : {

"bounds" : {

"northeast" : {

"lat" : 17.57944810,

"lng" : 78.69135810

},

"southwest" : {

"lat" : 17.23837080,

"lng" : 78.24014110

}

},

"location" : {

"lat" : 17.3850440,

"lng" : 78.4866710

},

"location_type" : "APPROXIMATE",

"viewport" : {

"northeast" : {

"lat" : 17.55533690,

"lng" : 78.74278980

},

"southwest" : {

"lat" : 17.21459250,

"lng" : 78.23055219999999

}

}

},

"types" : [ "locality", "political" ]

}

],

"status" : "OK"

}

2012-03-29 23: 56: 58.577 SVGeocoder [670: 11603]

####

2012-03-29 23: 56: 58.578 SVGeocoder [670: 11603] ########## (null)

1 Ответ

2 голосов
/ 30 марта 2012

Попробуйте это: 

- (CLLocationCoordinate2D) geoCodeUsingAddress: (NSString *) address
{
    CLLocationCoordinate2D myLocation; 

    NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];

    NSString *req = [NSString stringWithFormat: @"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];

    NSDictionary *googleResponse = [[NSString stringWithContentsOfURL: [NSURL URLWithString: req] encoding: NSUTF8StringEncoding error: NULL] JSONValue];

    NSDictionary *resultsDict = [googleResponse valueForKey:  @"results"];
    NSDictionary *geometryDict = [resultsDict valueForKey: @"geometry"];     
    NSDictionary *locationDict = [geometryDict valueForKey: @"location"];       
    NSArray *latArray = [locationDict valueForKey: @"lat"]; NSString *latString = [latArray lastObject];   
    NSArray *lngArray = [locationDict valueForKey: @"lng"]; NSString *lngString = [lngArray lastObject];    

    myLocation.latitude = [latString doubleValue];     
    myLocation.longitude = [lngString doubleValue];

    LogInfo(@"lat: %f\tlon:%f", myLocation.latitude, myLocation.longitude);
    return myLocation;
}
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