Конвертировать лямбда-выражение C # в VB - PullRequest
1 голос
/ 23 марта 2012

Рассматривая Нечеткий элемент управления выбора времени в C # .NET? Ответ Петра Чаплы на этот вопрос - именно то, что мне нужно.

К сожалению, я парень из VB.NET, и я не очень знаком с лямбда-выражениями, поэтому мои попытки конвертировать код привели к тому, что в течение нескольких часов меняли круглые скобки и били меня по голове кирпичом.1005 *

Есть ли шанс, что какой-нибудь двуязычный волшебник может преобразовать код C # в VB.net для меня?

Вот код, о котором идет речь:

class FuzzyDateTime
{

static List<string> dayList = new List<string>() { "sun", "mon", "tue", "wed", "thu", "fri", "sat" };
static List<IDateTimePattern> parsers = new List<IDateTimePattern>()
{
   new RegexDateTimePattern (
        @"next +([2-9]\d*) +months",
        delegate (Match m) {
            var val = int.Parse(m.Groups[1].Value); 
            return DateTime.Now.AddMonths(val);
        }
   ),
   new RegexDateTimePattern (
        @"next +month",
        delegate (Match m) { 
            return DateTime.Now.AddMonths(1);
        }
   ),           
   new RegexDateTimePattern (
        @"next +([2-9]\d*) +days",
        delegate (Match m) {
            var val = int.Parse(m.Groups[1].Value); 
            return DateTime.Now.AddDays(val);
        }
   ),

   new RegexDateTimePattern (
        @"([2-9]\d*) +months +ago",
        delegate (Match m) {
            var val = int.Parse(m.Groups[1].Value); 
            return DateTime.Now.AddMonths(-val);
        }
   ),
   new RegexDateTimePattern (
        @"([2-9]\d*) days +ago",
        delegate (Match m) {
            var val = int.Parse(m.Groups[1].Value); 
            return DateTime.Now.AddDays(-val);
        }
   ),
   new RegexDateTimePattern (
        @"([2-9]\d*) *h(ours)? +ago",
        delegate (Match m) {
            var val = int.Parse(m.Groups[1].Value); 
            return DateTime.Now.AddMonths(-val);
        }
   ),
   new RegexDateTimePattern (
        @"tomorrow",
        delegate (Match m) {
            return DateTime.Now.AddDays(1);
        }
   ),
   new RegexDateTimePattern (
        @"today",
        delegate (Match m) {
            return DateTime.Now;
        }
   ),
   new RegexDateTimePattern (
        @"yesterday",
        delegate (Match m) {
            return DateTime.Now.AddDays(-1);
        }
   ),
   new RegexDateTimePattern (
        @"(last|next) *(year|month)",
        delegate (Match m) {
            int direction = (m.Groups[1].Value == "last")? -1 :1;
            switch(m.Groups[2].Value) 
            {
                case "year":
                    return new DateTime(DateTime.Now.Year+direction, 1,1);
                case "month":
                    return new DateTime(DateTime.Now.Year, DateTime.Now.Month+direction, 1);
            }
            return DateTime.MinValue;
        }
   ),
   new RegexDateTimePattern (
        String.Format(@"(last|next) *({0}).*", String.Join("|", dayList.ToArray())), //handle weekdays
        delegate (Match m) {
            var val = m.Groups[2].Value;
            var direction = (m.Groups[1].Value == "last")? -1 :1;
            var dayOfWeek = dayList.IndexOf(val.Substring(0,3));
            if (dayOfWeek >= 0) {
                var diff = direction*(dayOfWeek - (int)DateTime.Today.DayOfWeek);
                if (diff <= 0 ) { 
                    diff = 7 + diff;
                }
                return DateTime.Today.AddDays(direction * diff);
            }
            return DateTime.MinValue;
        }
   ),

   new RegexDateTimePattern (
        @"(last|next) *(.+)", // to parse months using DateTime.TryParse
        delegate (Match m) {
            DateTime dt;
            int direction = (m.Groups[1].Value == "last")? -1 :1;
            var s = String.Format("{0} {1}",m.Groups[2].Value, DateTime.Now.Year + direction);
            if (DateTime.TryParse(s, out dt)) {
                return dt;
            } else {
                return DateTime.MinValue;
            }
        }
   ),
   new RegexDateTimePattern (
        @".*", //as final resort parse using DateTime.TryParse
        delegate (Match m) {
            DateTime dt;
            var s = m.Groups[0].Value;
            if (DateTime.TryParse(s, out dt)) {
                return dt;
            } else {
                return DateTime.MinValue;
            }
        }
   ),
};

public static DateTime Parse(string text)
{
    text = text.Trim().ToLower();
    var dt = DateTime.Now;
    foreach (var parser in parsers)
    {
        dt = parser.Parse(text);
        if (dt != DateTime.MinValue)
            break;
    }
    return dt;
}
}

interface IDateTimePattern
{
    DateTime Parse(string text);
}

class RegexDateTimePattern : IDateTimePattern
{
    public delegate DateTime Interpreter(Match m);
    protected Regex regEx;
    protected Interpreter inter;
    public RegexDateTimePattern(string re, Interpreter inter)
    {
        this.regEx = new Regex(re);
        this.inter = inter;
    }
    public DateTime Parse(string text)
    {
        var m = regEx.Match(text);

        if (m.Success)
        {
            return inter(m);
        }
        return DateTime.MinValue;
    }
}

Ответы [ 3 ]

3 голосов
/ 23 марта 2012

ОК, там куча кода, я не собираюсь переводить все это, кроме, например, ( при условии VS2010 или более поздней версии ). , .

new RegexDateTimePattern (
    @"next +([2-9]\d*) +months",
    delegate (Match m) {
        var val = int.Parse(m.Groups[1].Value); 
        return DateTime.Now.AddMonths(val);
    }
)

будет

    Dim p2 = New RegexDateTimePattern(
    "next +([2-9]\d*) +months",
    Function(m)
        Dim val = Int.Parse(m.Groups(1).Value)
        Return DateTime.Now.AddMonths(val)
    End Function
    )

и

new RegexDateTimePattern (
    String.Format(@"(last|next) *({0}).*", String.Join("|", dayList.ToArray())), 
    delegate (Match m) {
        var val = m.Groups[2].Value;
        var direction = (m.Groups[1].Value == "last")? -1 :1;
        var dayOfWeek = dayList.IndexOf(val.Substring(0,3));
        if (dayOfWeek >= 0) {
            var diff = direction*(dayOfWeek - (int)DateTime.Today.DayOfWeek);
            if (diff <= 0 ) { 
                diff = 7 + diff;
            }
            return DateTime.Today.AddDays(direction * diff);
        }
        return DateTime.MinValue;
    }
),

становится

    Dim p = New RegexDateTimePattern(
       String.Format("(last|next) *({0}).*", String.Join("|", dayList.ToArray())),
       Function(m)
           Dim val = m.Groups(2).Value
           Dim direction = If(m.Groups(1).Value = "last", -1, 1)
           Dim dayOfWeek = dayList.IndexOf(val.Substring(0, 3))
           If (dayOfWeek >= 0) Then
               Dim diff = direction * (dayOfWeek - CType(DateTime.Today.DayOfWeek, Integer))
               If (diff <= 0) Then
                   diff = 7 + diff
               End If
               Return DateTime.Today.AddDays(direction * diff)
           End If
           Return DateTime.MinValue
       End Function
       )

Есть ли что-нибудь еще, что крутит ваш меллон?

Если это не VS2010 (или даже если это так, и вам не нравятся лямбда-выражения), тогда все, что вам нужно сделать, это взять каждое из лямбда-выражений (функции "in line" в коде VB), создать явные именованные функции для каждой из них (например, RegexDateTimePattern_Helper2 для последней) и передать AddressOf RegexDateTimePattern_Helper2 вместо лямбда-выражения

1020 * т.е. *

    Function RegexDateTimePattern_Helper2(Match m) as DateTime ''# Dreadful name
        dim val = m.Groups[2].Value
        dim direction = if(m.Groups(1).Value = "last", -1 ,1)
        Dim dayOfWeek = dayList.IndexOf(Val.Substring(0, 3))
        If (dayOfWeek >= 0) Then
            Dim diff = direction * (dayOfWeek - CType(DateTime.Today.DayOfWeek, Integer))
            If (diff <= 0) Then
                diff = 7 + diff
            End If
            Return DateTime.Today.AddDays(direction * diff)
        End If
        Return DateTime.MinValue
    End Function

. , .

New RegexDateTimePattern (
    String.Format("(last|next) *({0}).*", String.Join("|", dayList.ToArray())), 
    AddressOf RegexDateTimePattern_Helper2)
0 голосов
/ 23 марта 2012

Я перевел один шаблон и все остальное.Теперь вам просто нужно добавить другие шаблоны (что не должно иметь большого значения. Это проверено в Module1.

Module Module1
    Sub Main()
        Dim res = FuzzyDateTime.Parse("next 2 months")
    End Sub
End Module

Public Interface IDateTimePattern
    Function Parse(text As String) As DateTime
End Interface

Public Class FuzzyDateTime
    Shared dayList As List(Of String) = New List(Of String)() From {"sun", "mon", "tue", "wed", "thu", "fri", "sat"}
    Shared parsers As List(Of IDateTimePattern) = New List(Of IDateTimePattern)()
    Shared Sub New()
        parsers.Add(New RegexDateTimePattern("next +([2-9]\d*) +months", New Func(Of Match, DateTime)(Function(x As Match)
                                                                                                          Dim val = Integer.Parse(x.Groups(1).Value)
                                                                                                          Return DateTime.Now.AddMonths(val)
                                                                                                      End Function)))
    End Sub
    Public Shared Function Parse(ByVal text As String) As DateTime
        text = text.Trim().ToLower()
        Dim dt = DateTime.Now
        For Each parser In parsers
            dt = parser.Parse(text)
            If Not dt = DateTime.MinValue Then
                Exit For
            End If
        Next
        Return dt
    End Function
End Class
Public Class RegexDateTimePattern : Implements IDateTimePattern
    Protected inter As Func(Of Match, DateTime)
    Protected regEx As Regex
    Public Function Parse(text As String) As Date Implements IDateTimePattern.Parse
        Dim m = regEx.Match(text)
        If m.Success Then Return inter(m)
        Return DateTime.MinValue
    End Function
    Public Sub New(ByVal re As String, ByVal inter As Func(Of Match, DateTime))
        Me.regEx = New Regex(re)
        Me.inter = inter
    End Sub
End Class

PS: я добавил шаблоны в статический конструктор (добавляйте их, где хотите, хотя), нельзя оценить с помощью встроенной инициализации - на мой взгляд, это просто безобразно.

0 голосов
/ 23 марта 2012

Преобразователь здесь выплевывает этот скомпилированный кусок кода (после удаления нескольких "Do" и пары "var"):

Imports System.Text.RegularExpressions

Class FuzzyDateTime

Shared dayList As New List(Of String)() From { _
 "sun", _
 "mon", _
 "tue", _
 "wed", _
 "thu", _
 "fri", _
 "sat" _
}
Shared parsers As New List(Of IDateTimePattern)() From { _
 New RegexDateTimePattern("next +([2-9]\d*) +months", Function(m As Match)
                                                          Dim val = Integer.Parse(m.Groups(1).Value)
                                                          Return DateTime.Now.AddMonths(val)
                                                      End Function), _
 New RegexDateTimePattern("next +month", Function(m As Match) DateTime.Now.AddMonths(1)), _
 New RegexDateTimePattern("next +([2-9]\d*) +days", Function(m As Match)
                                                        Dim val = Integer.Parse(m.Groups(1).Value)
                                                        Return DateTime.Now.AddDays(val)

                                                    End Function), _
 New RegexDateTimePattern("([2-9]\d*) +months +ago", Function(m As Match)
                                                         Dim val = Integer.Parse(m.Groups(1).Value)
                                                         Return DateTime.Now.AddMonths(-val)
                                                     End Function), _
 New RegexDateTimePattern("([2-9]\d*) days +ago", Function(m As Match)
                                                      Dim val = Integer.Parse(m.Groups(1).Value)
                                                      Return DateTime.Now.AddDays(-val)
                                                  End Function), _
 New RegexDateTimePattern("([2-9]\d*) *h(ours)? +ago", Function(m As Match)
                                                           Dim val = Integer.Parse(m.Groups(1).Value)
                                                           Return DateTime.Now.AddMonths(-val)
                                                       End Function), _
 New RegexDateTimePattern("tomorrow", Function(m As Match) DateTime.Now.AddDays(1)), _
 New RegexDateTimePattern("today", Function(m As Match) DateTime.Now), _
 New RegexDateTimePattern("yesterday", Function(m As Match) DateTime.Now.AddDays(-1)), _
 New RegexDateTimePattern("(last|next) *(year|month)", Function(m As Match)
                                                           Dim direction As Integer = If((m.Groups(1).Value = "last"), -1, 1)
                                                           Select Case m.Groups(2).Value
                                                               Case "year"
                                                                   Return New DateTime(DateTime.Now.Year + direction, 1, 1)
                                                               Case "month"
                                                                   Return New DateTime(DateTime.Now.Year, DateTime.Now.Month + direction, 1)
                                                           End Select
                                                           Return DateTime.MinValue
                                                           ''#handle weekdays
                                                       End Function), _
 New RegexDateTimePattern([String].Format("(last|next) *({0}).*", [String].Join("|", dayList.ToArray())), Function(m As Match)
                                                                                                              Dim val = m.Groups(2).Value
                                                                                                              Dim direction = If((m.Groups(1).Value = "last"), -1, 1)
                                                                                                              Dim dayOfWeek = dayList.IndexOf(val.Substring(0, 3))
                                                                                                              If dayOfWeek >= 0 Then
                                                                                                                  Dim diff = direction * (dayOfWeek - CInt(DateTime.Today.DayOfWeek))
                                                                                                                  If diff <= 0 Then
                                                                                                                      diff = 7 + diff
                                                                                                                  End If
                                                                                                                  Return DateTime.Today.AddDays(direction * diff)
                                                                                                              End If
                                                                                                              Return DateTime.MinValue

                                                                                                              ''# to parse months using DateTime.TryParse
                                                                                                          End Function), _
 New RegexDateTimePattern("(last|next) *(.+)", Function(m As Match)
                                                   Dim dt As DateTime
                                                   Dim direction As Integer = If((m.Groups(1).Value = "last"), -1, 1)
                                                   Dim s = [String].Format("{0} {1}", m.Groups(2).Value, DateTime.Now.Year + direction)
                                                   If DateTime.TryParse(s, dt) Then
                                                       Return dt
                                                   Else
                                                       Return DateTime.MinValue
                                                   End If
                                                   ''#as final resort parse using DateTime.TryParse

                                               End Function), _
 New RegexDateTimePattern(".*", Function(m As Match)
                                    Dim dt As DateTime
                                    Dim s = m.Groups(0).Value
                                    If DateTime.TryParse(s, dt) Then
                                        Return dt
                                    Else
                                        Return DateTime.MinValue
                                    End If
                                End Function) _
}

    Public Shared Function Parse(text As String) As DateTime
        text = text.Trim().ToLower()
        Dim dt = DateTime.Now
        For Each parser In parsers
            dt = parser.Parse(text)
            If dt <> DateTime.MinValue Then
                Exit For
            End If
        Next
        Return dt
    End Function
End Class

Interface IDateTimePattern
    Function Parse(text As String) As DateTime
End Interface

Class RegexDateTimePattern
    Implements IDateTimePattern
    Public Delegate Function Interpreter(m As Match) As DateTime
    Protected regEx As Regex
    Protected inter As Interpreter
    Public Sub New(re As String, inter As Interpreter)
        Me.regEx = New Regex(re)
        Me.inter = inter
    End Sub
    Public Function Parse(text As String) As DateTime Implements IDateTimePattern.Parse
        Dim m = regEx.Match(text)

        If m.Success Then
            Return inter(m)
        End If
        Return DateTime.MinValue
    End Function
End Class
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