Значения Json в цикле jQuery foreach

Question

Я получаю следующий JSON-ответ от сервера:

[{"id":"1","pid":"0","type":"Individual","code":"i","status":"1"},
 {"id":"2","pid":"0","type":"Group","code":"g","status":"1"},
 {"id":"15","pid":"0","type":"asdasd","code":"asd","status":"1"},
 {"id":"16","pid":"0","type":"asdas","code":"asd","status":"1"},
 {"id":"17","pid":"0","type":"my check","code":"mt","status":"1"}]

Как сделать цикл jQuery foreach и получить только значения id и type.

Answer 1

    var json = '[{"id":"1","pid":"0","type":"Individual","code":"i","status":"1"},{"id":"2","pid":"0","type":"Group","code":"g","status":"1"},{"id":"15","pid":"0","type":"asdasd","code":"asd","status":"1"},{"id":"16","pid":"0","type":"asdas","code":"asd","status":"1"},{"id":"17","pid":"0","type":"my check","code":"mt","status":"1"}]';
    $.each($.parseJSON(json), function() {
        alert(this.id + " " + this.type);
    });

Answer 2

var json = 
[
   {"id":"1","pid":"0","type":"Individual","code":"i","status":"1"},
   {"id":"2","pid":"0","type":"Group","code":"g","status":"1"},
   {"id":"15","pid":"0","type":"asdasd","code":"asd","status":"1"},
   {"id":"16","pid":"0","type":"asdas","code":"asd","status":"1"},
   {"id":"17","pid":"0","type":"my check","code":"mt","status":"1"}
];

$.each(json,function(i,el)
{
   alert(el.id+' - '+el.type);
});

Здесь - это глупый пример, выполняющийся

РЕДАКТИРОВАТЬ:

Как енойс сказал, что это может такжебыть достигнуто с помощью чистого JavaScript, который будет более быстрым решением. Здесь является эталоном зацикливания массивов в javascript и jQuery:

Answer 3

Рабочий образец здесь: http://jsfiddle.net/ezmilhouse/emCT8/

Фрагмент для создания нового массива объектов, который содержит только ключи id и type:

var json = [{"id":"1","pid":"0","type":"Individual","code":"i","status":"1"},{"id":"2","pid":"0","type":"Group","code":"g","status":"1"},{"id":"15","pid":"0","type":"asdasd","code":"asd","status":"1"},{"id":"16","pid":"0","type":"asdas","code":"asd","status":"1"},{"id":"17","pid":"0","type":"my check","code":"mt","status":"1"}];

var arr = [];
$.each(json, function(key, value){
    arr.push({
        id: value.id,
        type: value.type
    });
});

console.log(arr);

Answer 4

Попробуйте:

<script type="text/javascript">
$(document).ready(function () {
    var x = { "A" : {"A1": "1" } };
        $.each(x, function(i,v) {
            alert(i);
            console.log(i);
        });
});
</script>