Sql Pivot таблица с двумя кросс-таблицами и несколькими столбцами - PullRequest
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Sql Pivot таблица с двумя кросс-таблицами и несколькими столбцами

3 голосов
/ 19 февраля 2012

Я пытаюсь построить таблицу с двумя кросс-таблицами и несколькими столбцами. У меня это до сих пор, и когда я запускаю это 

    create table test2(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
    insert into test2 values ('Austin',  'African-American', 'male', 21)
    insert into test2 values ('Austin',  'Asian', 'female', 22)
    insert into test2 values ('Austin',  'Caucasian', 'male', 23)
    insert into test2 values ('Austin',  'Hispanic', 'female', 24)
    insert into test2 values ('Austin',  'African-American', 'Unknown', 25)
    insert into test2 values ('Austin',  'Asian', 'male', 26)
    insert into test2 values ('Austin',  'Caucasian', 'female', 27)
    insert into test2 values ('Austin',  'Hispanic', 'Unknown', 28)
    insert into test2 values ('Austin',  'Asian', 'male', 29)
    insert into test2 values ('Austin',  'Caucasian', 'female', 31)
    insert into test2 values ('Dallas',  'Hispanic', 'Unknown', 32)
    insert into test2 values ('Dallas',  'African-American', 'male', 33)
    insert into test2 values ('Dallas',  'Asian', 'female', 34)
    insert into test2 values ('Dallas',  'Caucasian', 'Unknown', 35)
    insert into test2 values ('Dallas',  'Hispanic', 'male', 500)
    insert into test2 values ('Dallas',  'African-American', 'female', 36)
    insert into test2 values ('Dallas',  'Asian', 'Unknown', 37)
    insert into test2 values ('Dallas',  'Caucasian', 'male', 38)
    insert into test2 values ('Dallas',  'Hispanic', 'female', 39)
    insert into test2 values ('Dallas',  'African-American', 'Unknown', 41)
    insert into test2 values ('Houston',  'Asian', 'male', 42)
    insert into test2 values ('Houston',  'Caucasian', 'female', 43)
    insert into test2 values ('Houston',  'Hispanic', 'Unknown', 44)
    insert into test2 values ('Houston',  'African-American', 'male', 45)
    insert into test2 values ('Houston',  'Asian', 'female', 46)
    insert into test2 values ('Houston',  'Caucasian', 'Unknown', 47)
    insert into test2 values ('Houston',  'Hispanic', 'male', 48)
    insert into test2 values ('Houston',  'African-American', 'female', 49)
    insert into test2 values ('Houston',  'Asian', 'Unknown', 51)
    insert into test2 values ('Houston',  'Caucasian', 'male', 52)

    SELECT  *
    FROM
    (
    SELECT  a.city, a.sex
    FROM [AdventureWorksDW].[dbo].[test2] a

    ) p
    PIVOT
    (
    COUNT (sex)
    FOR sex
    IN ([male], [female], [Unknown])
    ) AS pvt

Я понял

с http://realestateagenthealthinsurance.com/images/111.jpg

Но мне нужно вот что: две кросс-таблицы сверху и опция для нескольких столбцов.

с http://realestateagenthealthinsurance.com/images/222.jpg

Возможно ли это с помощью разворота или любого другого решения? Заранее спасибо

Ответы [ 2 ]

2 голосов
/ 19 февраля 2012 
WITH T AS (
    SELECT A.city,
           A.sex, 
           CASE
                WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
           END AS age_range_race
    FROM @test2 AS A
)
SELECT  *
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
       IN(
          [20-30_African-American], 
          [20-30_Asian], 
          [20-30_Caucasian], 
          [20-30_Hispanic],
          [31-40_African-American], 
          [31-40_Asian], 
          [31-40_Caucasian], 
          [31-40_Hispanic],
          [41-50_African-American], 
          [41-50_Asian], 
          [41-50_Caucasian], 
          [41-50_Hispanic]
          )
) AS P
ORDER BY city, sex
2 голосов
/ 19 февраля 2012

Вы можете запустить отдельный запрос PIVOT для каждой из 3 возрастных групп, а затем выполнить внешнее присоединение результатов к запросу города и пола: 

WITH DataKeys AS (
    select distinct city, sex
    from test2),
Data20to29 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 20 and 29
    ) AS Age20to29
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data20to29),
Data30to39 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 30 and 39
    ) AS Age30to39
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data30to39),
Data40to49 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 40 and 49
    ) AS Age40to49
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data40to49)
SELECT SELECT k.city, k.sex,
   d20.[African-American], d20.Asian, d20.Caucasian, d20.Hispanic,
   d30.[African-American], d30.Asian, d30.Caucasian, d30.Hispanic,
   d40.[African-American], d40.Asian, d40.Caucasian, d40.Hispanic
FROM DataKeys k LEFT JOIN Data20to29 d20 ON d20.city = k.city AND d20.sex = k.sex
LEFT JOIN Data30to39 d30 ON d30.city = k.city AND d30.sex = k.sex
LEFT JOIN Data40to49 d40 ON d40.city = k.city AND d40.sex = k.sex
ORDER BY k.city, k.sex
...