Получить сумму полей из таблицы MySQL, используя запрос

Question

у меня есть следующая таблица в моей базе данных ..

CREATE TABLE IF NOT EXISTS `client` (
  `CARD_NO` varchar(15) NOT NULL,
  `F_NAME` varchar(20) NOT NULL,
  `L_NAME` varchar(20) NOT NULL,
  `SEX` varchar(5) NOT NULL,
  `DOB` date NOT NULL,
  `SUBCITY` varchar(10) NOT NULL,
  `KEBELE` varchar(5) NOT NULL,
  `HOUSE_NO` varchar(10) NOT NULL,
  `TEL_NO` int(10) DEFAULT NULL,
  `REGION_NO` varchar(10) DEFAULT NULL,
  PRIMARY KEY (`CARD_NO`),
  KEY `REGION_NO` (`REGION_NO`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `client`
--

INSERT INTO `client` (`CARD_NO`, `F_NAME`, `L_NAME`, `SEX`, `DOB`, `SUBCITY`, `KEBELE`, `HOUSE_NO`, `TEL_NO`, `REGION_NO`) VALUES
('1', '', '', 'male', '0000-00-00', '', '', '', NULL, '01'),
('2', '', '', 'male', '0000-00-00', '', '', '', NULL, '02'),
('3', '', '', 'femal', '0000-00-00', '', '', '', NULL, '03'),
('4', '', '', 'femal', '0000-00-00', '', '', '', NULL, '04'),
('5', '', '', 'male', '0000-00-00', '', '', '', NULL, '05'),
('6', '', '', 'male', '0000-00-00', '', '', '', NULL, '05');

-- --------------------------------------------------------

--
-- Table structure for table `non_pregnant`
--

CREATE TABLE IF NOT EXISTS `non_pregnant` (
  `VCT_CODE` varchar(15) NOT NULL,
  `CARD_NO` varchar(15) DEFAULT NULL,
  `RISK_OF_HIV` varchar(30) NOT NULL,
  `PURPOSE` varchar(10) NOT NULL,
  PRIMARY KEY (`VCT_CODE`),
  KEY `CARD_NO` (`CARD_NO`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `non_pregnant`
--

INSERT INTO `non_pregnant` (`VCT_CODE`, `CARD_NO`, `RISK_OF_HIV`, `PURPOSE`) VALUES
('1', '1', '', ''),
('2', '2', '', ''),
('3', '3', '', ''),
('4', '4', '', ''),
('5', '5', '', ''),
('6', '6', '', '');

-- --------------------------------------------------------

--
-- Table structure for table `non_pregnant_vct`
--

CREATE TABLE IF NOT EXISTS `non_pregnant_vct` (
  `VCT_CODE` varchar(15) NOT NULL DEFAULT '',
  `DATE_TESTED` date DEFAULT NULL,
  `TB_RESULT` varchar(10) NOT NULL,
  `HIV_RESULT` varchar(10) NOT NULL,
  `STD_RESULT` varchar(10) NOT NULL,
  PRIMARY KEY (`VCT_CODE`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `non_pregnant_vct`
--

INSERT INTO `non_pregnant_vct` (`VCT_CODE`, `DATE_TESTED`, `TB_RESULT`, `HIV_RESULT`, `STD_RESULT`) VALUES
('1', NULL, '', 'pos', ''),
('2', NULL, '', 'pos', ''),
('3', NULL, '', 'neg', ''),
('4', NULL, '', 'neg', ''),
('5', NULL, '', 'neg', ''),
('6', NULL, '', 'pos', '');

-- --------------------------------------------------------

--
-- Table structure for table `region`
--

CREATE TABLE IF NOT EXISTS `region` (
  `REGION_NO` varchar(10) NOT NULL,
  `REGION_NAME` varchar(10) NOT NULL,
  PRIMARY KEY (`REGION_NO`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--
-- Dumping data for table `region`
--

INSERT INTO `region` (`REGION_NO`, `REGION_NAME`) VALUES
('01', 'washington'),
('02', 'newyork'),
('03', 'london'),
('04', 'paris'),
('05', 'burlin');

вот что я хочу в качестве вывода ..

Область, край женский мужчина Всего Тестовое задание положительный Тестовое задание положительный Тестовое задание положительный

и вот запрос, который я пытался выяснить, но все же не так ..

SELECT r.region_name, c.sex = 'male' as counting, c.sex = 'femal' as counting, v.hiv_result = 'pos' as MalePos from region r
left join client c
on c.region_no = r.region_no
left join non_pregnant p
on c.card_no = p.card_no
left join non_pregnant_vct v
on p.vct_code = v.vct_code
group by c.region_no;

Answer 1

Ваше описание результата, которое вы хотите, поразительно непонятно, но я попробую. Попробуйте это:

SELECT
    r.region_name,
    SUM(c.sex = 'male') as NMale,
    SUM(c.sex = 'femal') as NFemale,
    SUM(v.hiv_result = 'pos') as TotalPos,
    SUM(c.sex = 'male' AND v.hiv_result = 'pos') as MalePos,
    SUM(c.sex = 'femal' AND v.hiv_result = 'pos') as FemalePos
FROM region r
LEFT JOIN client c ON c.region_no = r.region_no
LEFT JOIN non_pregnant p ON c.card_no = p.card_no
LEFT JOIN non_pregnant_vct v ON p.vct_code = v.vct_code
GROUP BY c.region_no