Я собираюсь предположить, что вы понимаете, как повернуть изображение один раз. Если вы этого не сделаете, вы можете найти это с помощью быстрого поиска в Google.
Вам нужен фоновый процесс, который вращает его для вас. Это работает так:
/**
* Warning - this class is UNSYNCHRONIZED!
*/
public class RotatableImage {
Image image;
float currentDegrees;
public RotateableImage(Image image) {
this.image = image;
this.currentDegrees = 0.0f;
this.remainingDegrees = 0.0f;
}
public void paintOn(Graphics g) {
//put your code to rotate the image once in here, using current degrees as your rotation
}
public void spin(float additionalDegrees) {
setSpin(currentDegrees + additionalDegrees);
}
public void setSpin(float newDegrees) {
currentDegrees += additionalDegrees;
while(currentDegrees < 0f) currentDegrees += 360f;
while(currentDegrees >= 360f) currentDegrees -= 360f;
}
}
public class ImageSpinner implements Runnable {
RotateableImage image;
final float totalDegrees;
float degrees;
float speed; // in degrees per second
public ImageSpinner(RotatableImage image, float degrees, float speed) {
this.image = image;
this.degrees = degrees;
this.totalDegrees = degrees;
this.speed = speed;
}
public void run() {
// assume about 40 frames per second, and that the it doesn't matter if it isn't exact
int fps = 40;
while(Math.abs(degrees) > Math.abs(speed / fps)) { // how close is the degrees to 0?
float degreesToRotate = speed / fps;
image.spin(degreesToRotate);
degrees -= degreesToRotate;
/* sleep will always wait at least 1000 / fps before recalcing
but you have no guarantee that it won't take forever! If you absolutely
require better timing, this isn't the solution for you */
try { Thread.sleep(1000 / fps); } catch(InterruptedException e) { /* swallow */ }
}
image.setSpin(totalDegrees); // this might need to be 360 - totalDegrees, not sure
}
}