Мой вопрос о втором заявлении перерыва:
если x == xstart и y == ystart:
перерыв
Значит, это выражение break выходит за пределы правильного цикла true? Но затем он возвращается к следующему ближайшему циклу (а именно к доске while [x] [y] = OtherTile :) Но поскольку это условие не выполняется, он возвращается к исходному для цикла xdirection, цикла ydirection? Я просто хотел посмотреть, правильно ли я понял.
if board[xstart][ystart] not OnBoard(xstart, ystart) or board[xstart][ystart] != ' ':
return False
#temporarily set the tile on the board, but change it back to a blank before the end of this function
board[xstart][ystart] = tile
#Set computer tile
if tile == 'X':
OtherTile = 'O'
else:
OtherTile = 'X'
#empty list of tiles to flip
TilesToFlip = []
#this is a for loop for two variables. Each list of two represents a position away from the orignal spot
for xdirection, ydirection in [[1,0], [0,1], [-1,0], [0,-1], [1,-1], [1,1], [-1,1], [-1,-1]]:
#we set x and y to the original coordinates passed to us because we want to preserve the orignal values
x, y = xstart, ystart
x = x + xdirection
y = y + ydirection
#after the first iteration, check to see if the adjacent piece is on the board and if it's the OtherTile:
if isOnBoard(x,y) and board[x][y] == OtherTile:
x = x + xdirection
y = y + ydirection
#if the next piece is not on the board, go back to the for loop to test another direction
if not isOnBoard(x,y):
continue
while board[x][y] = OtherTile:
x = x + xdirection
y = y + ydirection
#we break here because if we had just continued it would have gone back to the while loop.
#since we're breaking, it goes back to the original for loop (if it goes off the board)
if not isOnBoard(x,y):
break
#it finishes with the while loop if it reaches a tile that is not the OtherTile (i.e. it's blank or it's the player's)
#so we check to see if it's the player's
if board[x][y] == tile:
#if it is the player's tile, then we go in the reverse direction, appending each tile to the TilesToFlip list
while True:
x = x - xdirection
y = y - ydirection
#when we reach the original tiles, we break (by then we have all the tiles that need to be flipped in store in the new list)
if x == xstart and y == ystart:
break
TilesToFlip.append([x,y])