Должно быть, я что-то здесь упустил.Я пытаюсь создать таблицу, но получаю сообщение об ошибке, сообщающее, что соединение все еще открыто.Но где???Я перечитал код, но не могу найти, где соединение все еще открыто ...
Проблема лежит здесь: objOleDbConnection.Open()
Ошибка говорит:
You attempted to open a database that is already opened by user 'Admin' on machine 'machine'. Try again when the database is available.
private void sfdNewFile_FileOk(object sender, System.ComponentModel.CancelEventArgs e)
{
// Creating a ADOX object needed to create
// new MS Access file.
ADOX.Catalog createMSFile = new ADOX.Catalog();
// Creating an object for a table.
Table nTable = new Table();
// Creating an object allowing me connecting to the database.
OleDbConnection objOleDbConnection = new OleDbConnection();
objOleDbConnection.ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;" +
"Data Source=" + sfdNewFile.FileName + ";Persist Security Info=False;Mode=12";
// Creating command object.
OleDbCommand objOleDbCommand = new OleDbCommand();
objOleDbCommand.Connection = objOleDbConnection;
try
{
// Created a new MS Access 2007 file with specified path.
createMSFile.Create("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" +
sfdNewFile.FileName);
objOleDbConnection.Open();
objOleDbCommand.CommandText = "CREATE TABLE PersonalData (" +
"[DataID] AUTOINCREMENT NOT NULL PRIMARY KEY ," +
"[Type] VARCHAR(40) NOT NULL ," +
"[URL] VARCHAR(40) NOT NULL ," +
"[SoftwareName] VARCHAR(40) NOT NULL ," +
"[SerialCode] VARCHAR(40) NOT NULL ," +
"[UserName] VARCHAR(40) NOT NULL ," +
"[Password] VARCHAR(40) NOT NULL";
objOleDbCommand.ExecuteNonQuery();
}
catch (Exception ex)
{
// Displaying any errors that
// might have occured.
MessageBox.Show("Error: " + ex.Message);
}
finally
{
// It is importnat to release COM object, in this very order
// otherwise we eill end up with an error.
System.Runtime.InteropServices.Marshal.FinalReleaseComObject(createMSFile);
// Closing the connection to the database.
objOleDbConnection.Close();
}
}