Мой исходный код, как показано ниже:
private static final String url = "jdbc:mysql://localhost/db_name";
private static final String user = "xxxx";
private static final String pswd = "xxxx";
private static final String sql = "SELECT * FROM table_name";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
LinearLayout linLayMain = new LinearLayout (this);
TextView txtViewMainTitle = new TextView (this);
TextView txtViewAdminName = new TextView (this);
TextView txtViewAdminPswd = new TextView (this);
txtViewMainTitle.setText ("Main Title : NONE");
txtViewAdminName.setText ("Admin Name : NONE");
txtViewAdminPswd.setText ("Admin Password : NONE");
try
{
Class.forName ("com.mysql.jdbc.Driver").newInstance ();
Connection con = (Connection) DriverManager.getConnection (url, user, pswd);
txtViewMainTitle.setText ("Main Title : JDBC Connection Sccess");
Statement st = con.createStatement ();
ResultSet rs = st.executeQuery (sql);
while (rs.next ())
{
txtViewAdminName.setText ("Admin Name : " + rs.getInt (1));
txtViewAdminPswd.setText ("Admin Pswd :" + rs.getString (2));
}
}
catch (Exception e)
{
Log.i ("Test GoSport", "Jdbc Error : " + e.getMessage());
e.printStackTrace ();
}
linLayMain.addView (txtViewMainTitle);
linLayMain.addView (txtViewAdminName);
linLayMain.addView (txtViewAdminPswd);
txtViewMainTitle.setLayoutParams (new LayoutParams (LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
txtViewAdminName.setLayoutParams (new LayoutParams (LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
txtViewAdminPswd.setLayoutParams (new LayoutParams (LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
setContentView (linLayMain);
}
Но это никогда не было успешным до сих пор. Когда я видел Log.i в DDMS, он всегда показывает «Ошибка соединения JDBC».
Моя среда, как показано ниже:
Mac OS X 10.7.2,
Eclipse Java EE Indigo,
MySQL-соединение-ява-5.1.18-bin.jar,
эмулятор 4.0.3, API 15