Я использую Hibernate 4 с простой «таблицей соединений» между двумя другими таблицами.Вот совместимые с JPA 1.0 сущности:
@Entity
@Table(name = "Companies")
public class Company
{
@Id
@Column
private Integer id;
@Column
private String name;
...
}
и
@Entity
@Table(name = "PQs")
public class PQ implements Serializable
{
@Id
@Column
private Integer id;
@Column
private String name;
...
}
Как вы можете видеть две подобные таблицы, просто простой идентификатор плюс имя.Теперь подключаемая сущность:
@Entity
@Table(name = "Partnerships")
@IdClass(value = PartnershipId.class)
public class Partnership implements Serializable
{
@Id
@Column(name = "pq_id", insertable = false, updatable = false)
private Integer pqId;
@Id
@Column(name = "company_id", insertable = false, updatable = false)
private Integer companyId;
@Column(name = "ordinal_nbr")
private Integer ordinalNbr;
@ManyToOne
@JoinColumn(name = "pq_id", referencedColumnName = "id")
private PQ pq;
@ManyToOne
@JoinColumn(name = "company_id", referencedColumnName = "id")
private Company company;
...
}
Обратите внимание на ... , insertable = false, updatable = false здесь @Column.
public class PartnershipId implements Serializable
{
private Integer pqId;
private Integer companyId;
public PartnershipId()
{
}
public PartnershipId(Integer pqId, Integer companyId)
{
this.pqId = pqId;
this.companyId = companyId;
}
...
}
При выполнении следующего кода теста
public class Main
{
private static String PERSISTENCE_UNIT_NAME = "standalonePu";
private static EntityManagerFactory emf;
private static EntityManager em;
private static EntityTransaction trans;
public static void main(String[] args)
{
setUp(PERSISTENCE_UNIT_NAME);
trans.begin();
PQ detachedPq = new PQ(1, "Test PQ");
Company detachedCompany = new Company(1, "Test Company");
PQ pq = em.merge(detachedPq);
Company company = em.merge(detachedCompany);
Partnership detachedPartnership = new Partnership(1, 1, 1);
detachedPartnership.setPQ(pq);
detachedPartnership.setCompany(company);
Partnership partnership = em.merge(detachedPartnership);
partnership = em.find(Partnership.class, new PartnershipId(1, 1));
System.out.println("Persistent partnership = ("
+ partnership.getPQId() + ", "
+ partnership.getCompanyId() + ", "
+ partnership.getOrdinalNbr() + ")");
trans.commit();
close();
}
private static void setUp(String puName)
{
emf = Persistence.createEntityManagerFactory(puName);
em = emf.createEntityManager();
trans = em.getTransaction();
}
private static void close()
{
em.close();
emf.close();
}
}
... Hibernate завершается с очень странным исключением на trans.commit();:
ERROR: Invalid argument in JDBC call: parameter index out of range: 4
Exception in thread "main" javax.persistence.RollbackException: Error while committing the transaction
at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:90)
at main.Main.main(Main.java:44)
Caused by: javax.persistence.PersistenceException: org.hibernate.exception.GenericJDBCException: Invalid argument in JDBC call: parameter index out of range: 4
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1347)
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1280)
at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:78)
... 1 more
Caused by: org.hibernate.exception.GenericJDBCException: Invalid argument in JDBC call: parameter index out of range: 4
at org.hibernate.exception.internal.SQLStateConverter.handledNonSpecificException(SQLStateConverter.java:148)
at org.hibernate.exception.internal.SQLStateConverter.convert(SQLStateConverter.java:136)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:124)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:109)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:131)
at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:80)
at $Proxy12.setInt(Unknown Source)
at org.hibernate.type.descriptor.sql.IntegerTypeDescriptor$1.doBind(IntegerTypeDescriptor.java:57)
at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:82)
at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:305)
at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:300)
at org.hibernate.type.ComponentType.nullSafeSet(ComponentType.java:358)
at org.hibernate.persister.entity.AbstractEntityPersister.dehydrate(AbstractEntityPersister.java:2599)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2836)
at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3276)
at org.hibernate.action.internal.EntityInsertAction.execute(EntityInsertAction.java:80)
at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:273)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:265)
at org.hibernate.engine.spi.ActionQueue.executeActions(ActionQueue.java:186)
at org.hibernate.event.internal.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:344)
at org.hibernate.event.internal.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:50)
at org.hibernate.internal.SessionImpl.flush(SessionImpl.java:1084)
at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:319)
at org.hibernate.engine.transaction.internal.jdbc.JdbcTransaction.beforeTransactionCommit(JdbcTransaction.java:100)
at org.hibernate.engine.transaction.spi.AbstractTransactionImpl.commit(AbstractTransactionImpl.java:173)
at org.hibernate.ejb.TransactionImpl.commit(TransactionImpl.java:73)
... 1 more
Caused by: java.sql.SQLException: Invalid argument in JDBC call: parameter index out of range: 4
at org.hsqldb.jdbc.Util.sqlException(Unknown Source)
at org.hsqldb.jdbc.Util.sqlException(Unknown Source)
at org.hsqldb.jdbc.Util.sqlException(Unknown Source)
at org.hsqldb.jdbc.Util.outOfRangeArgument(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.checkSetParameterIndex(Unknown Source)
at org.hsqldb.jdbc.JDBCPreparedStatement.setInt(Unknown Source)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:601)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:124)
... 22 more
Caused by: org.hsqldb.HsqlException: Invalid argument in JDBC call: parameter index out of range: 4
at org.hsqldb.error.Error.error(Unknown Source)
... 31 more
Протестированная конфигурация - Hibernate 4.0.0.CR4 и HSQLDB 2.0.Я также проверил это с MySQL 5 с очень одинаковым JDBC-исключением, поэтому очевидно, что Hibernate генерирует неправильный код.
Обходной путь для решения этой проблемы - поместить ..., insertable = false, updatable = false в отношения'@JoinColumn с, но это не совсем то, что я хочу.
Итак, это ошибка Hibernate?Приведенный выше код должен быть верным с точки зрения JPA ...