Я использую следующий код на Java в моей ОС Windows XP для архивирования папок. Это может быть по крайней мере полезно для вас как примечание.
//add folder to the zip file
private void addFolderToZip(String path, String srcFolder, ZipOutputStream zip) throws Exception
{
File folder = new File(srcFolder);
//check the empty folder
if (folder.list().length == 0)
{
System.out.println(folder.getName());
addFileToZip(path , srcFolder, zip,true);
}
else
{
//list the files in the folder
for (String fileName : folder.list())
{
if (path.equals(""))
{
addFileToZip(folder.getName(), srcFolder + "/" + fileName, zip,false);
}
else
{
addFileToZip(path + "/" + folder.getName(), srcFolder + "/" + fileName, zip,false);
}
}
}
}
//recursively add files to the zip files
private void addFileToZip(String path, String srcFile, ZipOutputStream zip,boolean flag)throws Exception
{
//create the file object for inputs
File folder = new File(srcFile);
//if the folder is empty add empty folder to the Zip file
if (flag==true)
{
zip.putNextEntry(new ZipEntry(path + "/" +folder.getName() + "/"));
}
else
{
//if the current name is directory, recursively traverse it to get the files
if (folder.isDirectory())
{
addFolderToZip(path, srcFile, zip); //if folder is not empty
}
else
{
//write the file to the output
byte[] buf = new byte[1024];
int len;
FileInputStream in = new FileInputStream(srcFile);
zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
while ((len = in.read(buf)) > 0)
{
zip.write(buf, 0, len); //Write the Result
}
}
}
}
//zip the folders
private void zipFolder(String srcFolder, String destZipFile) throws Exception
{
//create the output stream to zip file result
FileOutputStream fileWriter = new FileOutputStream(destZipFile);
ZipOutputStream zip = new ZipOutputStream(fileWriter);
//add the folder to the zip
addFolderToZip("", srcFolder, zip);
//close the zip objects
zip.flush();
zip.close();
}
private boolean zipFiles(String srcFolder, String destZipFile) throws Exception
{
boolean result=false;
System.out.println("Program Start zipping the given files");
//send to the zip procedure
zipFolder(srcFolder,destZipFile);
result=true;
System.out.println("Given files are successfully zipped");
return result;
}
В этом коде вам нужно вызвать предыдущий метод zipFiles(String srcFolder, String destZipFile), передав два параметра. Первый параметр указывает вашу папку для архивирования, а второй параметр destZipFile указывает вашу папку назначения.
Следующий код предназначен для распаковки заархивированной папки.
private void unzipFolder(String file) throws FileNotFoundException, IOException
{
File zipFile=new File("YourZipFolder.zip");
File extractDir=new File("YourDestinationFolder");
extractDir.mkdirs();
ZipInputStream inputStream = new ZipInputStream(new FileInputStream(zipFile));
try
{
ZipEntry entry;
while ((entry = inputStream.getNextEntry()) != null)
{
StringBuilder sb = new StringBuilder();
sb.append("Extracting ");
sb.append(entry.isDirectory() ? "directory " : "file ");
sb.append(entry.getName());
sb.append(" ...");
System.out.println(sb.toString());
File unzippedFile = new File(extractDir, entry.getName());
if (!entry.isDirectory())
{
if (unzippedFile.getParentFile() != null)
{
unzippedFile.getParentFile().mkdirs();
}
FileOutputStream outputStream = new FileOutputStream(unzippedFile);
try
{
byte[] buffer = new byte[1024];
int len;
while ((len = inputStream.read(buffer)) != -1)
{
outputStream.write(buffer, 0, len);
}
}
finally
{
if (outputStream != null)
{
outputStream.close();
}
}
}
else
{
unzippedFile.mkdirs();
}
}
}
finally
{
if (inputStream != null)
{
inputStream.close();
}
}
}